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2 years ago

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The Scatter plot below shows the linear trend of the number of golf carts a company sold the month of February and a line of bes

t fit representing this trend.
IT IS A DIFFERENT QUESTION FROM REPAIRING GOLF CARTS PLEASE READ

A. Write a function that models the number of golf carts sold as a function of the number of days in the month of February

B. What is the meaning of the slope as a rate of change for this line of best fit.

1 answer:

Andrei [34K]2 years ago

4 0

Answer:

Part A) $y=-5.625x+90$

Part B) see the explanation

Step-by-step explanation:

Part A) Write a function that models the number of golf carts sold as a function of the number of days in the month of February

Let

x ----> the number of days

y ----> the number of golf carts sold

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem

The y-intercept is the point (0,90)

so

$b=90$

Find the slope m

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

take two points from the graph

(0,90) and (16,0)

substitute the values in the formula

$m=\frac{0-90}{16-0}$

$m=\frac{-90}{16}$

simplify

$m=-\frac{45}{8}$ ---> is negative because is a decreasing function

therefore

The linear equation is equal to

$y=-\frac{45}{8}x+90$

Part B) What is the meaning of the slope as a rate of change for this line of best fit

The slope is $m=-\frac{45}{8}\ golf\ carts\ sold/days$

That means ----> every 8 days 45 less cars are sold

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Answer: Option A) $729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$ is the correct expansion.

Explanation:

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Here a=3c, $b=d^2$ and n=6,

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⇒ $(3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6$

⇒ $(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}$

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boyakko [2]

Answer:

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Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

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2 years ago

If cos(t) = 2/7 and t is in the 4th quadrant, find sin(t).

Yuliya22 [10]

We can use the Pythagorean Trigonometric Identity which says:
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Since we need to find sin(t), we have to solve for it:
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Let's plug in the given cos(t) value:
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And solve sin(t):
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Simplify further:
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And it all simplifies down to:
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Since it's in the 4th quadrant, the sin(t) value is going to be negative. So, your final answer is:
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Hope this helps!

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2 years ago