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storchak [24]
2 years ago
5

Raj is visiting the United States and needs to convert 2000 rupees to US dollars

Mathematics
2 answers:
Stells [14]2 years ago
7 0

Answer:

After converting Raj will have $31.88 USD

Step-by-step explanation:

1 unit rupee =  0.01594 USD

It is given that,

Raj is visiting the United States and needs to convert 2000 rupees to US dollars

<u>Convert 2000 rupees to USD</u>

To find USD we have to multiply rupees with 0.01594

USD = 2000*0.01594

USD = $31.88

Therefore Raj will have $31.88 USD

seropon [69]2 years ago
6 0

Answer:

$31.88 USD

Step-by-step explanation:

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Given ​ f(x)=x^2+12x+26 ​.
lapo4ka [179]

f(x)=x^2+12x+26

Vertex form of f(x) = a(x-h)^2 +k

We change f(x) into vertex form using completing the square method

f(x)=x^2+12x+26

We take half of square of middle term

middle term is 12

Half of square of 12 is \frac{12}{2}=6 then 6^2 = 36

Add and subtract 36 to complete the square

f(x)=(x^2+12x+36)+26-36

f(x)= (x+6)^2 +26 - 36 f(x)= (x+6)^2 -10

The vertex form f(x)= (x+6)^2 -10

6 0
1 year ago
Ming used the calculations shown to find out how much he would spend on 6 pounds of ground beef if 10 pounds of ground beef cost
Angelina_Jolie [31]

Answer:

He determined pounds per dollar by dividing 10 by 25 but wrote the unit rate as a dollar value.

Step-by-step explanation:

Given

\frac{10\ pounds}{\$25} = \frac{10\ pounds}{25} / \frac{\$25}{25} = \frac{0.4}{1}

Unit\ Price = 40\ cents

40\ cents * 6 = \$2.40

Required

Determine Ming's error

Ming's error is from here

\frac{10\ pounds}{\$25} = \frac{10\ pounds}{25} / \frac{\$25}{25} = \frac{0.4}{1}

He calculated the unit rate as pound per dollar.

So, after calculating the unit rate, the unit should be:

Unit\ Rate = 0.4\ pound/\$

But instead, he solved as:

Unit\ Rate = \$0.4/ pound

<em>Hence, (a) is correct</em>

5 0
2 years ago
Read 2 more answers
The solution to a quadric equation are x=2 and x=7. If k is a nonzero constant which of the following must be equal to the quadr
nikklg [1K]

Answer:

The quadratic equation form is x² - 9 x + 14  = 0            

Step-by-step explanation:

Given in the question as ,

The solution of quadratic equation are x = 2   and x = 7

The constant K is a non-zero number

Now , let the quadratic equation be , ax² + bx + c = 0

And  sum of roots = \frac{ - b}{a}

       product of roots = \frac{c}{a}

So, 2 + 7 = \frac{ - b}{a}

Or, 2 × 7 =  \frac{c}{a}

I.e \frac{ - b}{a}  = 9     ,     \frac{c}{a} = 14

Or,  b =  - 9 a           And c = 14 a

Put this value of b and c in standard form of quadratic equation

I.e ax² + bx + c = 0

Or, ax² - 9 ax + 14 a = 0

Or , a ( x² - 9 x + 14 ) = 0  

∴ a = 0   And  x² - 9 x + 14 = 0

Hence ,  The quadratic equation form is x² - 9 x + 14  = 0      Answer

7 0
1 year ago
In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
FrozenT [24]

Answer: The length of segments between this point and the vertices of greater base are 7\frac{5}{7} and 18.

Step-by-step explanation:

Let ABCD is the trapezoid, ( shown in below diagram)

In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7

Let P is the point where The extended legs meet,

So, according to the question, we have to find out : AP and BP

In Δ APB and Δ DPC,

∠ DPC ≅ ∠APB ( reflexive)

∠ PDC ≅ ∠ PAB    ( By alternative interior angle theorem)

And, ∠ PCD ≅ ∠ PBA  ( By alternative interior angle theorem)

Therefore, By AAA similarity postulate,

\triangle APB\sim \triangle D PC

Let, DP =x

⇒ \frac{3+x}{18} = \frac{x}{11}

⇒  33 +11x = 18x

⇒ x = 33/7= 4\frac{5}{7}

Thus, PD= 4\frac{5}{7}

But, AP= PD + DA

AP= 4\frac{5}{7}+3 =7\frac{5}{7}

Now, let PC =y,

⇒ \frac{7+y}{18} = \frac{y}{11}

⇒ 77 + 11y = 18y

⇒ y = 77/7 = 11

Thus, PC= 11

But, PB= PC + CB

PB= 11+7 = 18



7 0
1 year ago
For a package to qualify for a certain postage rate, the sum of its length and girth cannot exceed 85 inches. If the girth is 63
tester [92]

Answer:

Length of package can be = 22 inches

Step-by-step explanation:

Given:

For a package to qualify for a certain postage rate, the sum of its length and girth cannot exceed 85 inches

To find length of package when girth of package is = 63 inches

Solution:

Let length of package be = l inches

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Sum of length and girth of package = (l+g) inches  

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l+g\leq 85

We are given girth of package is = 63 inches

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l+63-63\leq 85-63

l\leq 22 inches

So, length should not exceed 22 inches in order to qualify.

Thus, the maximum length of package to qualify for the postal rate must be = 22 inches

3 0
2 years ago
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