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2 years ago

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4 lines are shown. 3 lines intersect and extend from one point forming 2 angles. The top angle is labeled 1 and the bottom angle

is labeled 2. A fourth line intersects all 3 lines. When it intersects the middle line, it forms 4 angles. Clockwise, from the top, the angles are 3, 6, 5, 4. When it intersects the third line, it forms 4 angles. Clockwise, from the top left, the angles are 7, 8, blank, blank.
Which angle pairs are supplementary? Check all that apply.

∠1 and ∠2

∠4 and ∠3

∠4 and ∠5

∠7 and ∠5

∠3 and ∠6

2 answers:

svp [43]2 years ago

8 0

Answer:

option b,c,e

Step-by-step explanation:

I just did this on edgen.

34kurt2 years ago

3 0

Answer:

B,C,E

Step-by-step explanation:

Edgenuity

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167.0067
I hope this helps!

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2 years ago

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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.

BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to $160\ ft^{2}$

Part b) The volume is equal to $240\ ft^{3}$

Part c) The volume water left in the trough will be $84\ ft^{3}$

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

$A=2[12*5]=120\ ft^{2}$

<em>Find the area of two trapezoids</em>

$A=2[\frac{1}{2}(8+2)h]$

Applying Pythagoras theorem calculate the height h

$h^{2}=5^{2}-3^{2}$

$h^{2}=16$

$h=4\ ft$

substitute the value of h to find the area

$A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}$

The exterior surface area is equal to

$120\ ft^{2}+40\ ft^{2}=160\ ft^{2}$

Part b) Find the volume

We know that

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=20\ ft^{2}$

$L=12\ ft$

substitute

$V=20(12)=240\ ft^{3}$

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

$A=\frac{1}{2}(5+2)(2)=7\ ft^{2}$

<em>step 2</em>

Find the volume

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=7\ ft^{2}$

$L=12\ ft$

substitute

$V=7(12)=84\ ft^{3}$

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2 years ago

Consider the set of differences, denoted with d, between two dependent sets: 84, 85, 83, 63, 61, 100, 98. Find the sample standa

sveta [45]

Answer:

The sample standard deviation is 15.3.

Step-by-step explanation:

Given data items,

84, 85, 83, 63, 61, 100, 98,

Number of data items, N = 7,

Let x represents the data item,

Mean of the data points,

$\bar{x}=\frac{84+85+83+63+61+100+98}{7}$

$=82$

Hence, sample standard deviation would be,

$\sigma= \sqrt{\frac{1}{N-1}\sum_{i=1}^{N} (x_i-\bar{x})^2}$

$=\sqrt{\frac{1}{6}\sum_{i=1}^{7} (x_i-82)^2}$

$=\sqrt{\frac{1}{6}\times 1396}$

$=\sqrt{232.666666667}$

$=15.2534149182$

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2 years ago

The density of granite is about 2.75 grams per cubic centimeter. Suppose you have a granite countertop for a kitchen that is 1 m

stellarik [79]

Answer:

$330\ kg$

Step-by-step explanation:

Remember that

1 kg=1,000 g

1 m= 100 cm

The volume of the granite countertop in cubic centimeters is equal to

$V=(100)(300)(4)\ cm^{3}$

The density in kg per cubic centimeter is equal to

$D=2.75(\frac{1}{1,000}) \frac{kg}{cm^{3}}$

Multiply the density by the volume

$2.75(\frac{1}{1,000})(100)(300)(4)$

$2.75(120)=330\ kg$

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2 years ago

A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 9 1/3 squar

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Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd

Area of parallelogram = base * height

We need to divide the combined area into two to get each parallelogram's base.

9 1/3 = ((9*3)+1)/3 = 28/3

28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²

Area of each parallelogram is 4 2/3 yd²

4 2/3 yd² = base * 1 1/3 yd

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14/3 yd² x 3/4 yd = base
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42 / 12 = base
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or 3 1/2 yd = base

a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.

length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds

Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²

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2 years ago

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