For a 30-60-90 triangle the sides always have the same relationship
Short leg = a
Long leg = a√3
Hypotenuse = 2a
BC is the short leg of ∆ABC
Given BC = 2
BC = a
Therefor
a = 2
AB = 2a = 4
AC = a√3 = 2√3
For ∆ACD
As above AC = 2√3
Since AC is the hypotenuse of ∆ACD
2a = 2√3
a = √3
CD = a = √3
AD = a√3 = 3
For ∆BCD
As above
BC = 2
CD = √3
Since BC is the hypotenuse of ∆BCD
2a = 2
a = 1
DB = a = 1
Answer:
0.033 ft
Step-by-step explanation:
Let g = 32.2 ft/s2 and h be the maximum height that water can be filled before the sides shatter.
Pressure is distributed from 0 to maximum at the bottom like the following equation:
So the force generated by water pressure on the side of the tank is
where s = 6ft is the side length of the tank. This force cannot be larger than 200lb
1.5r+15=2.25r
First of all, you have to arrange the numbers according to those similar to them. So that will be;
15=2.25r-1.5r
1.5r is subtracted from 2.25r because it crossed over an equality sign to get its position close to 2.25r. And when a number crosses over an equality sign, the sign on the number chages to the opposite. 1.5r has an invisible positive sign which became negative when it crossed. Anyway;
2.25r-1.5r is the same as 2.25-1.5. And that is 0.75r
Therefore;
15=0.75r
To find out what r is, you have to divide the both sides by 0.75. This is done to remove the 0.75 close to r to finally reveal what r is. Anyway;
15/0.75=0.75r/0.75
15 divided by 0.75 is 20. And 0.75r divided by 0.75 is r. So;
20=r
r=20. So the answer is 20 movies. Hope i helped. Have a nice day.
1. Consider square ABCD. You know that
then
2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that
3. Consider trapezoid BFGC. Its area is
where h is the height of trapezoid and is equal to half of AB. Thus,
4.
5. Note that angles EGC and CGD are supplementary and
Then
Answer: 
