Answer:
StartRoot 53 EndRoot units
XY = √53
Step-by-step explanation:
Choose which is point 1 and point 2 so you don't confuse the coordinates.
Point 1 (–4, 0) x₁ = –4 y₁ = 0
Point 2 (3, 2) x₂ = 3 y₂ = 2
Use the formula for the distance between two points.




Therefore the line of segment XY is √53.
. . . . . . .. . . . . . . . . . . . . . . . . . . . ./ . . . . . . . . . . . . . . . . . . . . . . . . . . . .
Provide the approximated measurement to associate the volume of water.
Answer:
Rebecca does not have a return yet because the stock was not sold since there was a limit order at $33.
However, the value of her investment can be put around $2,400 (100 x $24 average price).
Step-by-step explanation:
Price of Havad Stock bought a year ago = $20
No. of shares = 100
Limit order selling price = $33
Stock prices during the limit order day = $23, $26, and $22
The stock cannot be sold, since its price did not reach $33.
Rebecca's limit order is an order to buy or sell her stock in Havad at $33 or better. Since her order is a sell limit order, it can only be executed at the limit price of $33 or higher. Unfortunately, the price of the stock did not reach the limit order on that particular day. This implies that her limit order is not guaranteed to execute.
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let
be the random variable that follows a Poisson distribution, then mean 
and the mean that the random selection of 50 pages will contain no error is 
∴

Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
![P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B%20%5Cdfrac%7Be%5E%7B-1%7D%201%5E0%7D%7B0%21%7D%20%2B%5Cdfrac%7Be%5E%7B-1%7D%201%5E1%7D%7B1%21%7D%20%5D)
![P(X \geq 2) = 1 - [0.3678 +0.3678]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B0.3678%20%2B0.3678%5D)

P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644