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Lana71 [14]
2 years ago
11

What is the step by step solution to 30m=80+22m thank you

Mathematics
1 answer:
ratelena [41]2 years ago
8 0

Answer:

-10

Step-by-step explanation:

30m - 22m =80 therefore m is equal to -10

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What is the length of segment XY?
Brilliant_brown [7]

Answer:

StartRoot 53 EndRoot units

XY = √53

Step-by-step explanation:

Choose which is point 1 and point 2 so you don't confuse the coordinates.

Point 1 (–4, 0)    x₁ = –4   y₁ = 0

Point 2 (3, 2)      x₂ = 3    y₂ = 2

Use the formula for the distance between two points.

L = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}

XY = \sqrt{(3-(-4))^{2} + (2-0)^{2}}

XY = \sqrt{49 + 4}

XY = \sqrt{53}

Therefore the line of segment XY is √53.

6 0
2 years ago
Read 2 more answers
True or false: the regression sum of squares (ssr) can never be greater than the total sum of squares (sst).
Valentin [98]
. . . . . . .. . . . . . . . . . . . . . . . . . . . ./ . . . . . . . . . . . . . . . . . . . . . . . . . . . . 
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2 years ago
A museum has a 1/1000 scale model of the Grand Canyon, complete with a miniature river in the bottom. Explain how you could use
defon
Provide the approximated measurement to associate the volume of water.
3 0
2 years ago
Question 2 (1 point)
hichkok12 [17]

Answer:

Rebecca does not have a return yet because the stock was not sold since there was a limit order at $33.

However, the value of her investment can be put around $2,400 (100 x $24 average price).

Step-by-step explanation:

Price of Havad Stock bought a year ago = $20

No. of shares = 100

Limit order selling price = $33

Stock prices during the limit order day = $23, $26, and $22

The stock cannot be sold, since its price did not reach $33.

Rebecca's limit order is an order to buy or sell her stock in Havad at $33 or better. Since her order is a sell limit order, it can only be executed at the limit price of $33 or higher.  Unfortunately, the price of the stock did not reach the limit order on that particular day.  This implies that her limit order is not guaranteed to execute.

8 0
2 years ago
A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat
DiKsa [7]

Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

and the mean that the random selection of 50 pages will contain no error is \lambda = 50 \times 0.02 =1

∴

Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

P(X \geq 2) = 1 - [0.3678 +0.3678]

P(X \geq 2) = 1 -0.7356

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0
2 years ago
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