On a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system.

terrence made a sphere out of modeling clay. the sphere had a radius of 2 inches. approximately how much modeling clay did terre

navik [9.2K]

Amount of clay used = volume of the sphere

It is given that the radius of the sphere is 2 inches.

Volume of the sphere = $\frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2^{3} )$

$=\frac{4}{3} \pi (8)$

$=\frac{32}{3} \pi$

Hence, the amount of modeling clay Terrence used $=\frac{32}{3} \pi$ cubic inches.

5 0

2 years ago

4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

So

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

6 0

2 years ago

A carnival has two payment options. Plan A, you pay $10 admission plus $3 for each ride. Plan B, you pay a $20 admission plus $1

stiks02 [169]

<span>Let x = # of rides

Plan A: 10 + 3x

Plan B: 20 + x

if x < 5 rides then plan A is better buy
if x = 5 both plans are the same
if x > 5 then plan B is the best buy

Prove:
x = 6 (rides)

plan A: </span>10 + 3x = 10 + 3(6) = 10+18 = $28
plan B: 20 + x = 20 + 6 = $26

3 0

2 years ago

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The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =

madreJ [45]

So we are given a system:
$3x-2y+3z=0\\
-3x - 5y - 5z= -21$
Substitute x = 2 we get the system:
$-2y+3z=-6\\
- 5y - 5z= -15$
Multiply the first equation by -5 and the second by 2 we get the system:
$10y-15z=30\\
- 10y - 10z= -30$
Adding the two equations we get :
$-25z=0\text{ then}z=0.$
We find the value of y by using any of the other equations like this:
$-2y=-6\\y=3.$
Final solution:
$z=0,y=3$

8 0

2 years ago

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Brahmagupta solved a quadratic equation of the form ax2 + bx = c using the formula x =, which involved only one solution. Using

weeeeeb [17]

X2+7x-8=0
product=-8 times 1 = -8
sum= 7
{-1, 8}
x2-1x+8x-8=0
x(x-1)+8(x-1)=0
x+8=0 or X-1=0
x=-8

4 0

1 year ago

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