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Norma-Jean [14]

1 year ago

15

Lisa wrote the following statement: "You can only draw one unique isosceles triangle that contains an angle of 65°." Which state

ment is true

1 answer:

JulijaS [17]1 year ago

4 0

Triangles always equal 180 degrees

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Pete’s return from selling his investment is $22,000. He had purchased the investment at a cost of $20,000. What is Pete’s retur

Effectus [21]

Answer:

Option C

10%

Step-by-step explanation:

Given information

Cost of investment=$20000

Selling price=$22000

Profit=Selling price-Cost of investment=22000-20000=2000

Return on investment=profit/cost of investment

$RoI=\frac {2000\times 100}{20000}=10%$

6 0

2 years ago

The source document states: (S) The process takes three hours to complete. The new document states: (S) The first step in the pr

Dmitry [639]

Answer:

Contained in.

Step-by-step explanation:

The correct answer to given question is "contained in". This is because of the fact that it was extracted as it was stated in the source or authorized document without any need to add any information, analyze or interpret the information in the new document.

4 0

1 year ago

Read 2 more answers

Mr. Beecher and Mrs. Carter are teachers at the same school. They leave their houses at the same time in the morning to get to s

timofeeve [1]

Let the school be at point x

Mr. Beecher lives 8 miles away from school

Therefore, his starting point is x – 8

Every minute, he gets 1/6 of a mile closer to school

Therefore, at time, t(in minutes), Mr. Beecher’s distance from school, Db = x – 8 + (1/6)t

Db = x – 8 + (1/6)t … (Equation I)

Mrs. Carter lives 20 miles away from school

Therefore, her starting point is x – 20

Every minute, she gets 1/2 of a mile closer to school

Therefore, at time, t(in minutes), Mrs. Carter’s distance from school, Dc = x – 20 + (1/2)t

Dc = x – 20 + (1/2)t … (Equation II)

After how many minutes will Mr. Beecher and Mrs. Carter first be the same distance away from school?

That’s when Db = Dc, given that t is same value in both equations

Db = x – 8 + (1/6)t … (Equation I)

Dc = x – 20 + (1/2)t … (Equation II)

Db = Dc. Therefore,

x – 8 + (1/6)t = x – 20 + (1/2)t

Subtract x from both sides of the equation

x – x – 8 + (1/6)t = x – x – 20 + (1/2)t

– 8 + (1/6)t = – 20 + (1/2)t

(1/6)t – 8 = (1/2)t – 20

Add 20 to both sides of the equation

(1/6)t – 8 + 20 = (1/2)t – 20 + 20

(1/6)t + 16 = (1/2)t

(1/2)t = (1/6)t + 16

Subtract (1/6)t from both sides of the equation

(1/2)t – (1/6)t = (1/6)t – (1/6)t + 16

1/3t = 16

Multiply both sides of the equation by 3

1/3t x 3 + 16 x 3

t = 48 minutes

Therefore, after 48 minutes, Mr. Beecher and Mrs. Carter will first be the same distance away from school.

6 0

2 years ago

A study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. Th

andrey2020 [161]

Answer:

The requirements are satisifed since we have the proportion estimated, the sample sizes provided, we assume random sampling for the selection of the data and the distribution for the difference of proportions can be considered as normal

$z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923$

Step-by-step explanation:

The requirements are satisifed since we have the proportion estimated, the sample sizes provided, we assume random sampling for the selection of the data and the distribution for the difference of proportions can be considered as normal

Data given and notation

$n_{M}=41$ sample of male selected

$n_{W}=56$ sample of demale selected

$p_{M}=0.57$ represent the proportion of men who dislike anchovies

$p_{WCB}=0.84$ represent the proportion of women who dislike anchovies

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men is different from women , the system of hypothesis would be:

Null hypothesis: $p_{M} = p_{W}$

Alternative hypothesis: $p_{M} \neq p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{0.67+0.84}{2}=0.755$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923$

4 0

2 years ago

Simplify these expressions.<br> a. 4x + 7x + (–x)<br> b. –5yz + yz + 2yz

salantis [7]

Answer:A. 10x. B. -2yz

Step-by-step explanation:

A. 4x+7x=11x

11x+(-x) = 11x-1x=10x

B. -5yz+yz=-4yz

-4yz+2yz=-2yz

4 0

1 year ago