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1 year ago

Choose the two expressions that are equivalent to 5. 75 ÷ 1. 15

Mathematics

2 answers:

PSYCHO15rus [73]1 year ago

8 0

Answer:

A and B

Step-by-step explanation:

kirill [66]1 year ago

5 0

Answer:

A and B, but I’m gonna explain it the best I can too.

Step-by-step explanation:

5.75 divided by 1.15 is the same as answer A, since all you are doing is taking away the periods, making it whole numbers.

Again 5.75 divided by 1.15 is the same as B as well, Since it is the same just without the periods and an added zero at the end of each.

This Is so that they are both all equivalent by being whole numbers, but whatever you do to one numbers in the expression that you think is the answer you have to do to the other numbers in the expression

they have to add up completely the same.

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A circular backyard pool has a diameter of 26 feet and is 4 feet deep. One cubic foot of water has a capacity of approximately 7

klasskru [66]

Find the water volume of the pool. The formula for a vertical cylinder is V = pi*r^2*h, which here is V = pi(13 ft)^2*(4 ft) = 676*pi cubic feet.

Now convert this 676 cu. ft. to gallons:

Mult (676*pi cu ft) by the conversion factor (7.48 gal) / (1 cu ft):

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--------------- * ------------- = 5056*pi gallons (rounded down from 5056.48 pi)
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2 years ago

Determine the input value for which the statement f(x) = g(x) is true. From the graph, the input value is approximately_______ .

Julli [10]

In this question , we have a graph given, and we have to find the x coordinate of the intersection point .

From the graph , the input value is approximately 3.3 .

In the graph,

$f(x) =3$

And for g(x), we need the slope and y intercept .

Slope is the ratio of rise and run .

Here rise equals 3 units and run equals 2 units. And the graph touch the y axis at -2 .

So the equation of g(x) is

$g(x) = \frac{3}{2}x -2$

We need to do

$f(x)= g(x)$

Substituting the values of the two functions, we will get

$3 = \frac{3}{2}x -2$

Adding 2 to both sides

$5 = \frac{3}{2}x$

Cross multiplication

$10 =3x
\\
x = \frac{10}{3}$

$x = 3.3$

So the input value is 3.3 approx

6 0

1 year ago

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Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

SOVA2 [1]

$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

The arc length of the curve is

$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

so that the arc length is approximately

$\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086$

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2 years ago

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White raven [17]

Answer:

domain: All real numbers

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Step-by-step explanation:

Edge 2020

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1 year ago

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Artyom0805 [142]

Answer:

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b) Narrower

c) Wider

Step-by-step explanation:

We are given the following in the question:

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$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

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If we increase the sample size, thus the standard error of the interval decreases.

Since the standard error decreases, the confidence interval become narrower.

b) Confidence level had been 90% instead of 98%

As the confidence level increases, the confidence interval becomes narrower. This is due to a smaller value of z-statistic at 90% confidence level.

c) Confidence level had been 99% instead of 98%

As the confidence level increases, the width of the confidence interval increases and the confidence interval become wider. This is because of a larger value of z-statistic at 99% confidence interval.

4 0

2 years ago