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mezya [45]
2 years ago
6

WHOEVER GETS IT RIGHT GETS BRAINLIEST

Mathematics
1 answer:
Nikolay [14]2 years ago
6 0
2(1.25x+3)=23.5
2.5x+6=23.5
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Function ggg can be thought of as a scaled version of f(x)=x^2f(x)=x 2 f, left parenthesis, x, right parenthesis, equals, x, squ
emmainna [20.7K]

Answer:

g(x)=15/20 x^2

Step-by-step explanation:

write 15/20 as a fraction then x^2 comes after it

I took the khan test and aced it

5 0
2 years ago
Read 2 more answers
A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip. On the return route, the boat trav
Georgia [21]

<em><u>The intervals included in solution are:</u></em>

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

<em><u>Solution:</u></em>

Given that,

A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip

On the return route, the boat travels against the current, decreasing the boat's rate by 10 mph

The group needs to travel an average of at least 24 mph

<em><u>Given inequality is:</u></em>

\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}

<em><u>We have to solve the inequality</u></em>

\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}\\\\\frac{2}{x}  - 10\geq \frac{2}{24}

\mathrm{Subtract\:}\frac{2}{24}\mathrm{\:from\:both\:sides}\\\\\frac{2}{x}-10-\frac{2}{24}\ge \frac{2}{24}-\frac{2}{24}\\\\Simplify\\\\\frac{2}{x}-10-\frac{2}{24}\ge \:0

\frac{2}{x}-\frac{10}{1}-\frac{2}{24} \geq 0\\\\\frac{ 2 \times 24}{x \times 24} -\frac{10 \times 24}{1 \times 24} - \frac{2 \times x }{24 \times x}\geq 0\\\\\frac{48}{24x}-\frac{240x}{24x}-\frac{2x}{24x}\geq 0\\\\Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions\\\\\frac{48-240x-2x}{24x}\geq 0\\\\Add\:similar\:elements\\\\\frac{48-242x}{24x}\ge \:0

\mathrm{Multiply\:both\:sides\:by\:}24\\\\\frac{24\left(48-242x\right)}{24x}\ge \:0\cdot \:24\\\\Simplify\\\\\frac{48-242x}{x}\ge \:0\\\\Factor\ common\ terms\\\\\frac{-2\left(121x-24\right)}{x}\ge \:0\\\\\mathrm{Multiply\:both\:sides\:by\:}-1\mathrm{\:\left(reverse\:the\:inequality\right)}

When we multiply or divide both sides by negative number, then we must flip the inequality sign

\frac{\left(-2\left(121x-24\right)\right)\left(-1\right)}{x}\le \:0\cdot \left(-1\right)\\\\\frac{2\left(121x-24\right)}{x}\le \:0\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{\frac{2\left(121x-24\right)}{x}}{2}\le \frac{0}{2}\\\\Simplify\\\\\frac{121x-24}{x}\le \:0

\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{121x-24}{x}\\

This is attached as figure below

From the attached table,

\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0\\\\0

<em><u>Therefore, solution set is given as</u></em>:

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

8 0
2 years ago
Read 2 more answers
Consider the incomplete paragraph proof. Given: Isosceles right triangle XYZ (45°–45°–90° triangle) Prove: In a 45°–45°–90° tria
Norma-Jean [14]

Answer:

(C)Determine the principal square root of both sides of the equation.

Step-by-step explanation:

Given: Isosceles right triangle XYZ (45°–45°–90° triangle)

To Prove: In a 45°–45°–90° triangle, the hypotenuse is \sqrt{2} times the length of each leg.

Proof:

\angle XYZ$ is 90^\circ$ and the other 2 angles are 45^\circ. \\\overline{XY} = a, \overline{YZ}= a, \overline{XZ}= c.\\

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a^2 + b^2 = c^2

Since a=b in an isosceles triangle:

a^2 + a^2 = c^2\\$Combining like terms\\2a^2 = c^2\\$Determine the principal square root of both sides of the equation.\\\sqrt{c^2}=\sqrt{2a^2}  \\\\c=a\sqrt{2} \\

Therefore, the next step is to Determine the principal square root of both sides of the equation.

8 0
1 year ago
Read 2 more answers
Which expression shows the distance on the number line between 2 and −7?
AlladinOne [14]
D because they are 9 ponits between them so the abs are going going to remove the negative
4 0
2 years ago
Read 2 more answers
Suppose bug A lands on the end of the blade farthest from the pivot. Assume the wiper turns through an angle of 120°. In one cyc
ruslelena [56]

Answer:

s = 21.33*π in

Step-by-step explanation:

Given:

- The complete data is given in the figure (attached):

Solution:

- The bugs lands on the end of the wiper blade furthest to the pivot. The arc length (s) swept by a wiper in one cycle i.e θ = 120° would be given by:

                                    s = 2*r*θ

- Where, r: The distance between the bug and the pivot = 16 in  

              θ : Angle swept in radians

- The distance travelled by the bug is s:  

                                   s = 2*(16)*( 120 / 180 ) * π  

                                   s = 21.33*π in

3 0
1 year ago
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