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krek1111 [17]
1 year ago
11

Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang

e. f(x) has a restricted domain. f(x) has an x-intercept of (2, 0). f(x) has a maximum at the point (0, 2). f(x) has a y-intercept at the point (0, 2).
Mathematics
2 answers:
PolarNik [594]1 year ago
5 0

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence  f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence  f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx  = 2x

since  d(fx))/dx  = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

atroni [7]1 year ago
3 0

Answer:

A,B,E

Step-by-step explanation:

2021 Edgenutity. Algebraric reasoning B

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Answer:

a) \bar X = \frac{\sum_{i=1}^n X_i}{n}

And for this case if we use this formula we got:

\bar x = 1.3538

b) Since we have n =16 values for the sample the median can be calculated as the average between position 8th anf 9th and we got:

Median = \frac{1.31+1.46}{2}= 1.385

c) P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=1.3538 +1.28*0.3505=1.8024

So the value of height that separates the bottom 90% of data from the top 10% is 1.8024.  

d) Median= \frac{x_{8} +x_{9}}{2}

The variance for this estimator is given by:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} Var(X_{8} +X_{9})

We can assume the obervations independent so then we have:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} (2\sigma^2) = \frac{\sigma^2}{2}

And replacing we got:

Var(\frac{x_{8} +x_{9}}{2})= \frac{0.3105^2}{2}= 0.0482

And the standard error would be given by:

Sd(\frac{x_{8} +x_{9}}{2})= \sqrt{0.0482}=0.2196

Step-by-step explanation:

Data given:

0.86 0.88 0.88 1.07 1.09 1.17 1.29 1.31  1.46 1.49 1.59 1.62 1.65 1.71 1.76 1.83

Part a

We can calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And for this case if we use this formula we got:

\bar x = 1.3538

Part b

For this case in order to calculate the median we need to put the data on increasing way like this:

0.86 0.88 0.88 1.07 1.09 1.17 1.29 1.31 1.46 1.49  1.59 1.62 1.65 1.71 1.76 1.83

Since we have n =16 values for the sample the median can be calculated as the average between position 8th anf 9th and we got:

Median = \frac{1.31+1.46}{2}= 1.385

Part c

For this case we can assume that the mean is \mu = 1.3538

And we can calculate the population deviation with the following formula:

\sigma = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{N}}

And if we replace we got:  \sigma= 0.3105

And assuming normal distribution we have this:

X \sim N (\mu = 1.3538, \sigma= 0.3105)

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P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

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P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=1.3538 +1.28*0.3505=1.8024

So the value of height that separates the bottom 90% of data from the top 10% is 1.8024.  

Part d

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Median= \frac{x_{8} +x_{9}}{2}

The variance for this estimator is given by:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} Var(X_{8} +X_{9})

We can assume the obervations independent so then we have:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} (2\sigma^2) = \frac{\sigma^2}{2}

And replacing we got:

Var(\frac{x_{8} +x_{9}}{2})= \frac{0.3105^2}{2}= 0.0482

And the standard error would be given by:

Sd(\frac{x_{8} +x_{9}}{2})= \sqrt{0.0482}=0.2196

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<h3><u>Solution:</u></h3>

Given that,

Baby Amelia's parents measure her height every month

It is given that H(t) models Amelia's height (in centimeters) when she was "t" months old

Given statement is H(30) = H(25) + 5

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