Answer:
Option B
Step-by-step explanation:
Options for the given question -
A.
A histogram
B.
A cumulative frequency table
C.
A pie chart
D.
A frequency polygon
Solution
Option B is correct
The data represents the frequency value for a given interval and hence it represents the cumulative form of frequency distribution.
Answer:
Options A, B and E represent mutually exclusive events.
Step-by-step explanation:
Two events are mutually exclusive that can not happen at a same time.
Now let us look at our options and find which statements represent mutually exclusive events.
A. We can see that landing on an unshaded portion and landing on 2 are mutually exclusive events as unshaded portion contains 3 and 4 and 2 lies on shaded portion.
B. Landing on a shaded portion and landing on 3 is also mutually exclusive as 3 lies on unshaded portion.
C. Landing on a shaded portion and landing on an even number can happen at the same time as 2 is an even number and it lies on shaded portion.
D. Landing on an unshaded portion and landing on a number greater than 3 can happen at the same time as 4 in greater than 3 and it lies on unshaded portion.
E. Landing on a shaded portion and landing on an unshaded portion are mutually exclusive events as spinner can be either in shaded portion or in unshaded portion.
Therefore, Options A, B and E are our correct choices.
Answer:
Answer is given below under explanation
Step-by-step explanation:
We are told that the domain is a set of real numbers. Let's depict by a & b.
We will use the following symbols;
∀ means for all
Ǝ there exists
∧ means logical conjuction
Thus;
A) Ǝ a,b : ( a/b < 1, b/a < 1 )
B) ∀ a : ( a > 0 = 1/a > 0 )
C) Ǝ a,b : (a + b = ab)
D) ∀ a,b : [ ( a > 0 ) ∧ ( b > 0 ) = (( a/b > 0 ) ∧ ( b/a > 0 ))]
E) ∀ b : [( b > 0 ) ∧ ( b < 1) = ( 1/b > 1 )]
F) n ( ( Ǝ x ∀ b ( a < b ) )
Answer:
for 5 probability is 1/6
for not a five = 1-1/6 = 5/6
Step-by-step explanation:
