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Genrish500 [490]
1 year ago
6

A shopper seeking a bargain combined a 25% off coupon and brought enough money to cover 25% of the base price. Why did this shop

per go home disappointed?
Mathematics
1 answer:
zheka24 [161]1 year ago
7 0

Let's pretend the base price is $100

If the shopper brings enough money to cover 25% of the base price then they are bringing $25

The bargain promises 25% off of the base price of $100, meaning that the bargain price will be $75

The shopper cannot purchase the item because they only brought $25 when they should have brought $75

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At a large company, employees can take a course to become certified to perform certain tasks. There is an exam at the end of the
WINSTONCH [101]

Answer:

A Type II error is when the null hypothesis is failed to be rejected even when the alternative hypothesis is true.

In this case, it would represent that the new program really increases the pass rate, but the sample taken is not enough statistical evidence to prove it. Then, the null hypothesis is not rejected.

The consequence is that the new method would be discarded (or changed) eventhough it is a real improvement.

Step-by-step explanation:

5 0
2 years ago
The cost of an item is 100% of its price. What number goes in place of ? in the addition problem?
Dmitry_Shevchenko [17]
I believe this is the complete problem. 

<span>Anton bought a picnic cooler. His total bill, with tax, was $7.95. He paid 6 percent sales tax. How much did he pay for the cooler alone without the tax? The cost of an item is 100% of its price. What number goes in place of ? in the addition problem?
</span>
The answer is the below:

<span>He paid $7.473 without tax because $7.95 x 96% or (0.96) =$7.473</span>
8 0
1 year ago
Read 2 more answers
Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1
astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

x^{2} - 24 = 1

Given that resulting expression is a second order polynomial of the form x^{2} - a^{2}, there are two real and distinct solutions. Roots of the expression are:

x_{1} = -5 and x_{2} = 5.

Now, it is also required to determine which part of the interval (x_{1}, x_{2}) is equal to a number greater than zero (positive). That is:

x^{2} - 24 > 0

x^{2} > 24

x < -4.899 and x > 4.899.

Therefore, exists two sub-intervals: [-5, -4.899] and \left[4.899,5\right]. Besides, x^{2} - 24 > y = 1 in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx

A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx

A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}

A = 2.525 -2.474+9.798 + 2.525 - 2.474

A = 9.9\,units^{2}

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

4 0
1 year ago
Solve the following by factoring 4x² + 12 =7x
LiRa [457]

Answer:

4x² + 12 = 7x

4x² + 12 - 7x = 0

use the quadratic formula and get your answer!

Step-by-step explanation:

3 0
2 years ago
The singing club keeps sheet music in files. Each file holds 12 sheets. Of all the club's music, 2/3 fit into 3 files. How many
laila [671]
1 file -> 12 sheets

Now for 3 files -> 3*12 = 36 sheets, it takes up 2/3 of the total

So the total number of sheets: 36 / (2/3) = 54
6 0
2 years ago
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