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1 year ago

How to find the sum of the forces in the y direction of an elevator?

1 answer:

6 0

A cardboard box rests on the floor of an elevator. The box has a mass m = 3.75 kg and the elevator has an upward acceleration of a

Part a. Select the Free Body Diagram for the system
Part b. Write an expression for the sum of the forces actinv on the box in the y direcion, given that up is the positive y direction. Your answer should be in terms of FN, m, g.
Part c. Write an expression for the normal force FN, that the block experiences in terms of the elevator's accelaration, the block's mass and the accelaration of gravity
Part d. If the elevator's accelaration has a magnitude of g in the downward direction, what would the normal force FN1 be in Newtons? (Numerical value)
Part e. If the elevator's accelaration had a magnitude of g in the upward direction, what would the normal force FN2 ve in Newtons? (Numerical value)

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A probability calculator is required on this problem; answer to six decimal places. Suppose we will spin the wheel pictured 400

KiRa [710]

Answer:

$P(90< X< 110)= P(\frac{90-80}{8}$

And we can find this probability with this difference:

$P(90< X< 110)=P(z$

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=400, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=400*0.2=80 \geq 10$

$n(1-p)=400*(1-0.2)=320 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=400*0.2=80$

$\sigma=\sqrt{np(1-p)}=\sqrt{400*0.2(1-0.2)}=8$

So then we can approximate the random variable as $X \sim N(\mu = 80, \sigma = 8)$

And we want this probability:

$P(90< X< 110)$

We can use the z score formula given by:

$z = \frac{x -\mu}{\sigma}$

And replacing we got:

$P(90< X< 110)= P(\frac{90-80}{8}$

And we can find this probability with this difference:

$P(90< X< 110)=P(z$

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

8 0

2 years ago

A jet flying at 123 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2

aev [14]

Answer:

The magnitude of the necessary lifting force is 7.95N

Step-by-step explanation:

Force = mv^2/r

mass (m) = 2.00105kg, velocity (v) = 123m/s, radius (r) = 3810m

Force = 2.00105×123^2/3810 = 30273.89/3810 = 7.95N

7 0

1 year ago

Essica is a custodian at Oracle Arena. She waxes 20 \text{ m}^220 m 2 20, space, m, start superscript, 2, end superscript of the

Butoxors [25]

261828372wdjdnendjdnjdhdhss

7 0

1 year ago

Employment data at a large company reveal that 74% of the workers are married, 42% are college graduates, and that 56% are marri

ValentinkaMS [17]

Answer:

(E) None of these above are true.

Step-by-step explanation:

Married = 74% or 0.74

College graduates = 42% or 0.42

pr(married | college graduates) = 0.56

(A) These events are pairwise disjoint. This is false. Pairwise disjoint are also known as mutually exclusive events. Here we can see that both events are occurring at same time.

(B) These events are independent events. This is also false.

(D) A worker is either married or a college graduate always. False

Here Probability(A or B) shall be 1

= Pr(A) + Pr(B) - Pr( A and B) = 0.74 + 0.42 - 0.56 * 0.42 = 0.9248

This is not equal to 1.

(E) None of these above are true. This is true.

8 0

2 years ago

The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(

prisoha [69]

I included the graphs of the functions f(x) (given in blue) and g(x) (given in red) in the attached pdf file.

The questions are:

1) Find u(1) and
2) Find v(1)

Solutions:

1) u(x) = f(x) g(x) => u(1) = f(1) * g(1)

From the graphs f(1) = 1 and g(1) = 2, then f(1)*g(1) = 1*2 =2

Answer: 2

2) v(x) = f(x) / g(x) => v(1) = f(1) / g(1) = 1 / 2 = 0.5

Answer: 0.5

Download pdf

8 0

1 year ago