Answer:
a) 0.9644 or 96.44%
b) 0.5429 or 54.29%
Step-by-step explanation:
a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)
P(A) = 1 - P(N) .....1
Given;
Total number of cards = 140
Number selected = 20
Total number of defective cards = 20
Total number of non defective cards = 140-20 = 120
P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.
P(N) = 120C20/140C20 = 0.0356
From equation 1
P(A) = 1 - 0.0356
P(A) = 0.9644 or 96.44%
b) Using the same method as a) above
P(A) = 1 - P(N) .....1
Given;
Total number of cards = 140
Number selected = 20
Total number of defective cards = 5
Total number of non defective cards = 140-5 = 135
P(N) = 135C20/140C20 = 0.457
From equation 1
P(A) = 1 - 0.4571
P(A) = 0.5429 or 54.29%
Given
jacinta buys 4 pounds of turkey and 2 pounds of ham & pays a total of $30, turkey costs $1.50 less per pound than the ham.
find out the combined cost of 1 pound of turkey and 1 pound of ham
To proof
As given in the question
jacinta buys 4 pounds of turkey and 2 pounds of ham
total pay by jacinta = $30
let us assume that the price of the ham = x
as given in the question
turkey costs $1.50 less per pound than the ham
turkey costs becomes = x - 1.50
then the equation becomes
30 = 4 (x - 1.50) + 2x
30 = 4x + 2x - 6
36 = 6x
x = 6
thus
ham cost per pound = $6
turkey cost per pound = 6 - 1.50
= $ 4.5
Now find out
cost of 1 pound of turkey + 1 pound of ham = $ 6 + $ 4.5
= $ 10.5
Hence proved
SIx boys can eat seven (7) hotdogs in six (6) minutes.
(x) is an element of a real number. This means it could be an integer, fraction or irrational number.
* As x approaches infinity, y approaches infinity.
* As x approaches minus infinity, y approaches 0.
-------------
Domain:
(x) is an element of a real number
Range:
y>0
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution
