Ask question

Ask question

All categories

2 years ago

10

Thomas is saving money for a new mountain bike. The amount (a) Thomas needs to save is more than $50.45. Which inequality models

the amount Thomas needs to save?
A.$50.45=a
B.$60.45 C.a>$50.45
D.a<$50.45

1 answer:

AfilCa [17]2 years ago

3 0

C.

This is because the amount is more than what he needs to save, considering that he is probably has some money in his bank already.

You might be interested in

Susan’s business makes handmade dresses. The business sells three different kinds of dresses: evening gowns, sundresses, and coc

nordsb [41]

Answer:

45

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which subtraction sentences show you how to find 15-7

Alborosie

First you need to divide 7 and 15, and the answer you get is 8, so 8+7=15. 8 will be your answer.

8 0

2 years ago

Read 2 more answers

What is the multiplicative rate of change for the exponential function f(x) = f start bracket x end bracket equals two start bra

jeka94

Answer:

The multiplicative rate of change is $\dfrac{2}{5}.$

Step-by-step explanation:

You are given the function

$f(x)=2\cdot \left(\dfrac{5}{2}\right)^{-x}$

First, use the following property of exponents

$\left(\dfrac{a}{b}\right)^{-x}=\left(\dfrac{b}{a}\right)^{x}$

So, your function is

$f(x)=2\cdot \left(\dfrac{2}{5}\right)^{x}$

If the exponential function is written in the form

$f(x)=a\cdot b^x,$

then b is the multiplicative rate of change for this exponential function.

In your case, the multiplicative rate of change is $\dfrac{2}{5}.$

7 0

2 years ago

Read 2 more answers

A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like

mixas84 [53]

Answer:

a) $\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) $\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) the steady state mass of the drug is 2000 mg

d) t ≅ 153.51 minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

$Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min$

$Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min$

Therefore;

$\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}$

with respect to x(0) = 0

$\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}$

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

$\dfrac{dx}{dt} = -0.015(x - 2000)$

$\dfrac{dx}{(x - 2000)} = -0.015 \times dt$

By Using Integration Method:

$ln(x - 2000) = -0.015t + C$

$x -2000 = Ce^{(-0.015t)$

$x = 2000 + Ce^{(-0.015t)}$

However; if x(0) = 0 ;

Then

C = -2000

Therefore

$\mathbf{x = 2000 - 2000e^{-0.015t}}$

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

$\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}$

x = 2000 - 0

x = 2000

Thus; the steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

$\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}$

$0.1 = e^{(-0.015t)$

$ln(0.1) = -0.015t$

$t = -\dfrac{In(0.1)}{0.015}$

t = 153.5056729

t ≅ 153.51 minutes

4 0

2 years ago

Which expression is equivalent to mc003-1.jpg?

Nookie1986 [14]

Answer:

Option A is correct

The expression which is equivalent to $(f\cdot g)(5)$ is $f(5) \cdot g(5)$

Step-by-step explanation:

Using the formula:

$(f \cdot g)(x) = f(x) \cdot g(x)$ .....[1]

Given the expression:

$(f\cdot g)(5)$

Substitute the value of x = 5 in [1]

we get;

$(f \cdot g)(5) = f(5) \cdot g(5)$

Therefore, the expression which is equivalent to $(f\cdot g)(5)$ is $f(5) \cdot g(5)$

8 0

2 years ago

Read 2 more answers