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2 years ago

Max finds the product 3/7 x 6. Which statement is true?

1 answer:

3 0

The correct answer is choice B. When you are multiplying anything by a value greater than one, the answer you get will always be bigger than what you started with.

The reason lies with in the concept of multiplication.

If you have more than one group of something, you will have more than what you started with.

You might be interested in

At a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least o

tatyana61 [14]

Answer:

Option b

Step-by-step explanation:

Given that at a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least once, and 37.5 percent of the students who walk to school have been late to school at least once.

Proportions of Students coming late to school = coming by walk and late to school + coming by other means and late to school = 0.32 (given)

Proportions of students coming late atleast once and by walk

= 40% * 375%

= $0.4(0.375)\\=0.15$

the probability that the student selected will be one who both walks to school and has been late to school at least once

=0.15

(option b)

7 0

2 years ago

How many extraneous solutions does the equation below have? StartFraction 2 m Over 2 m + 3 EndFraction minus StartFraction 2 m O

xeze [42]

Answer:

Step-by-step explanation:

We have the fraction $\frac{2m}{2m+3} -\frac{2m}{2m-3}$

Step 1. Use LCM of the fraction, (2m+3)(2m-3), to simplify the fraction:

$\frac{(2m-3)(2m)-(2m+3)(2m)}{(2m+3)(2m-3)} =\frac{2m^2-6m-[2m^2+6m]}{(2m+3)(2m-3)} =\frac{2m^2-6m-2m^2-6m}{(2m+3)(2m-3)} =\frac{-12m}{(2m+3)(2m-3)}$

Step 2. Equate the resulting fraction to zero and solve for $m$ :

$\frac{-12m}{(2m+3)(2m-3)} =0$

$-12m=0[(2m+3)(2m-3)]$

$-12m=0$

$m=\frac{0}{-12}$

$m=0$

Step 3. Replace the value in the original equation and check if it holds:

$\frac{-12m}{(2m+3)(2m-3)} =0$

$-12m=0$

Since $m=0$ ,

$-12(0)=0$

$0=0$

Since the only solution of the equation holds, the equation bellow doesn't have any extraneous solution

5 0

2 years ago

Read 2 more answers

The angle Johnny holds his pen on paper creates a linear pair. The measure of one angle is 13x+7. The measure of the second angl

lisov135 [29]

we know that

Angles in a linear pair are supplementary angles

Let

A-------> the first angle

B------> the second angle

$A+B=180\\$ ----> equation $1$

$A=13x+7\\ B=2A-1=B=26x+13$

Substitute the values of A and B in the equation $1$

$13x+7+26x+13=180\\ 39x=180-20\\ x=\frac{160}{39}$

$\frac{160}{39}=4.10\ degrees$

therefore

the answer is

the value of x is $4.10\ degrees$

5 0

2 years ago

Read 2 more answers

Swati recorded this data set, which contains an outlier. 163, 97, 184, 199, 169, 175 What numbers represent the lower and upper

arsen [322]

To determine the answers to this item, we are to arranged the given data points in increasing order. The arrangement would then be,

97,163, 169, 175, 184, 199

The lower quartile is the median of the lower half of the data points. In this case, 97, 163, 169. The median is equal to 163

The upper quartile is the median of the upper half of the data points. In this case, 175, 184, 199. The median is equal to 184.

Hence, the aswers to this item is that lower quartile is equal to 163 and upper quartile is equal to 184. The first option.

6 0

2 years ago

Read 2 more answers

Consider the following random sample from a normal population: 14, 10, 13, 16, 12, 18, 15, and 11. What is the 95% confidence in

seraphim [82]

Answer:

$13.625-2.365\frac{2.669}{\sqrt{8}}=11.393$

$13.625+2.365\frac{2.669}{\sqrt{8}}=15.857$

So on this case the 95% confidence interval would be given by (11.393;15.857)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 14, 10, 13, 16, 12, 18, 15, 11

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=13.625$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.669 represent the sample standard deviation

n=8 represent the sample size

Calculate the confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=8-1=7$

Since the confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that $t_{\alpha/2}=2.365$

Now we have everything in order to replace into formula (1):

$13.625-2.365\frac{2.669}{\sqrt{8}}=11.393$

$13.625+2.365\frac{2.669}{\sqrt{8}}=15.857$

So on this case the 95% confidence interval would be given by (11.393;15.857)

3 0

2 years ago