The markup percentage is 45.14%
Step-by-step explanation:
The given is:
- The selling price of a box of crackers is $1.75
- You mark the crackers up to $2.54
We need to find the markup percentage
The markup percentage =
× 100%
∵ The selling price of a box of crackers is $1.75
∴ Old = 1.75
∵ You mark the crackers up to $2.54
∴ New = 2.54
- Substitute these values in the rule above
∵ The markup percentage =
× 100%
∴ The markup percentage =
× 100%
∴ The markup percentage = 0.4514 × 100%
∴ The markup percentage = 45.14%
The markup percentage is 45.14%
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4.509 is greater that 4.508 and less than 4.512
Answer:
I dont even know
Step-by-step explanation:
too complicated
Given:
Q = 0.0764 kJ = 764 J, heat input
W = -830 J, useful work done
From the 1st Law of Thermodynamics, the change in internal energy is
δE = Q - W
= 764 - (-830)
= 1594 J = 1.594 kJ
Answer: 1.59 kJ (two sig. fig.)
Answer:
the speed btn sonya and issac would make a right angled trangle hence easy 2 solve through pythogoras

then find the
![\sqrt[?]{?}](https://tex.z-dn.net/?f=%20%5Csqrt%5B%3F%5D%7B%3F%7D%20)
hence get 45
since it was 12 mins we need 2 multiply by 12
hence

Therefore it's 540mph