Answer:
The correct answer is No.
Choosing between the critical value method or the P-value method does not affect one's conclusion because both methods look at the probability of the test statistic's and its level of significance
.
Given the methodology utilized by both methods, they usually arrive at the same conclusion.
Cheers!
T is a linear function of C ==> T = mC + b
Each additional chirp C corresponds to an increase in T of 0.25 ==> m = 0.25
T = 52 when C = 20 ==> 52 = 0.25(20) + b ==> b = 52 - 5 = 47
So T = 0.25C + 47
When C = 100 then T = 0.25(100) + 47 = 25 + 47 = 72
When C = 120 then T = 0.25(120) + 47 = 30 + 47 = 77 so the
temperature range is between 72 and 77 when there are between 100 and
120 chirps per minute
For the last part, you have to find where
attains its maximum over
. We have

so that

with critical points at
such that





So either

or

where
is any integer. We get 8 solutions over the given interval with
from the first set of solutions,
from the set of solutions where
, and
from the set of solutions where
. They are approximately






Remember
a²-b²=(a-b)(a+b)
8x²-50y²
2(4x²-25y²)
(2)([2x]²-[5y]²)
2(2x-5y)(2x+5y)
Answer:
Intercepts at (-1, 0) and (0, 1).
Step-by-step explanation:
The double intercept form for the equation of a line is
ax + by = 1
-1 = -y + x
<em> y = 0
</em>
<em> </em>x = -1 Multiply each side by -1
-x = 1
The <em>x-intercept</em> is at (-1, 0).
=====
<em> x = 0
</em>
-1 = -y Multiply each side by -1
y = 1
The <em>y-intercept</em> is at (0, 1).
=====
The graph (see below) is a straight line passing through the points (-1, 0) and (0, 1).