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Y_Kistochka [10]
2 years ago
6

A barber shop produces 96 haircuts a day. each barber in the shop works 8 hours per day and produces the same number of haircuts

per hour. if the shop's productivity is 2 haircuts per hour of labor, then how many barbers does the shop employ?
Mathematics
1 answer:
Finger [1]2 years ago
7 0
We know that
A barber shop produces 96 haircuts a day----------> <span>8 hours per day
so
96/8--------> 12 haircuts per hour

if </span><span>if the shop's productivity is 2 haircuts per hour of labor
then
12/2---------> 6 </span><span>barbers

the answer is
6 </span><span>barbers</span>
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In hypothesis​ testing, does choosing between the critical value method or the​ P-value method affect your​ conclusion? Explain.
Artist 52 [7]

Answer:​

The correct answer is No.

Choosing between the critical value method or the P-value method does not affect one's conclusion because both methods look at the probability of the test​ statistic's and its level of significance .

Given the methodology utilized by both methods, they usually arrive at the same conclusion.

Cheers!

8 0
2 years ago
The function C(t) below relates outside temperature in degrees Fahrenheit to the number of cricket chirps per minute. It takes a
vekshin1
T is a linear function of C  ==>  T = mC + b     Each additional chirp C corresponds to an increase in T of 0.25  ==>  m = 0.25    T = 52 when C = 20  ==>  52 = 0.25(20) + b  ==>  b = 52 - 5 = 47   So T = 0.25C + 47    When C = 100 then T = 0.25(100) + 47 = 25 + 47 = 72   When C = 120 then T = 0.25(120) + 47 = 30 + 47 = 77 so the temperature range is between 72 and 77 when there are between 100 and 120 chirps per minute 
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2 years ago
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The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas
iren [92.7K]

For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

so that

f''(t)=-18\cos3t-12\sin2t

with critical points at t such that

-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

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2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

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4 0
2 years ago
What is the completely factored form 8x2-50y2?
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Remember
a²-b²=(a-b)(a+b)

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7 0
2 years ago
Use the double intercept approach to find the graph of –1 = –y + x. A. B. C. D.
navik [9.2K]

Answer:

Intercepts at (-1, 0) and (0, 1).

Step-by-step explanation:

The double intercept form for the equation of a line is

ax + by = 1

-1 = -y + x

<em> y = 0 </em>

<em> </em>x = -1     Multiply each side by -1

-x = 1

The <em>x-intercept</em> is at (-1, 0).

=====

<em> x = 0 </em>

-1 = -y     Multiply each side by -1

y = 1

The <em>y-intercept</em> is at (0, 1).

=====

The graph (see below) is a straight line passing through the points (-1, 0) and (0, 1).


5 0
2 years ago
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