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givi [52]
2 years ago
11

Find the balance in the account. $800 principal earning 7%, compounded annually, after 4 years

Mathematics
2 answers:
Alinara [238K]2 years ago
8 0
Use the compound amount formula:  A = P (1+r)^t

Here,

A = $800 (1+0.07)^4  = $800 ( 1.31) = $1048.64 (rounded off to the nearest cent)
scoray [572]2 years ago
6 0
800×(1.07)^(4) =1,048.63
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Answer:

StartFraction 7 over 2 EndFraction can be used to find the unit rate if one divides 7 by 2 and compares the result to 1

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points

B(2, 7) and D(4, 14)

substitute the values

m=\frac{14-7}{4-2}

m=\frac{7}{2}

The unit rate is

m=\frac{3.5}{1}

therefore

StartFraction 7 over 2 EndFraction can be used to find the unit rate if one divides 7 by 2 and compares the result to 1

7 0
2 years ago
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KiRa [710]

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Money Market Instruments

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2 years ago
Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

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2 years ago
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Answer:

50 chance

Step-by-step explanation:

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To make a reflection over the y axis, make the whole equation negative. 
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