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givi [52]
2 years ago
11

Find the balance in the account. $800 principal earning 7%, compounded annually, after 4 years

Mathematics
2 answers:
Alinara [238K]2 years ago
8 0
Use the compound amount formula:  A = P (1+r)^t

Here,

A = $800 (1+0.07)^4  = $800 ( 1.31) = $1048.64 (rounded off to the nearest cent)
scoray [572]2 years ago
6 0
800×(1.07)^(4) =1,048.63
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Anna wants to take fitness classes. She compares two gyms to determine which would be the best deal for her. Fit Fast charges a
steposvetlana [31]
This is sort of weird to write without any numbers, but it's not too hard. take your info out of the word problem:

fit fast = fee per class
stepping up = fee per class + monthly fee

now you just change all of that into variables, essentially:

F = cx
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2 years ago
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Ivanshal [37]
1,650 is the answer to your question
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2 years ago
The binomial (y − 2) is a factor of y2 − 10y + 16. What is the other factor?
PtichkaEL [24]

Answer:

\left(y-8\right)

Step-by-step explanation:

y^2-10y+16

=\left(y^2-2y\right)+\left(-8y+16\right)

y^2-2y

=yy-2y

=y\left(y-2\right)

-8y+16

=-8y+8\cdot \:2

=-8\left(y-2\right)

=y\left(y-2\right)-8\left(y-2\right)

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The other factor is:

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2 years ago
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Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
trasher [3.6K]

For this case, the first thing we must do is define variables.

We have then:

t: the time in minutes

k: the number of kilometers

The relationship between both variables is direct.

Therefore, the function is:

k (t) = c * t

Where, "c" is a constant of proportionality.

To determine "c" we use the following data:

After running for 18 minutes, she completes 2 kilometers.

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c = \frac{2}{18}

c = \frac{1}{9}

Then, the equation is given by:

k (t) = \frac{1}{9} * t

Answer:

An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

k (t) = \frac{1}{9} * t

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2 years ago
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frosja888 [35]
A guest orders a drink = <span>1½ ounces of 80-proof vodka and 12 ounces of beer
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