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finlep [7]
2 years ago
8

There are 1,000 golden delicious and 1,000 red delicious apples in a cooler. In a random sample of 75 of the golden delicious ap

ples, 48 had blemishes. In a random sample of 75 of the red delicious apples, 42 had blemishes. Assume all conditions for inference have been met. Which of the following is closest to the interval estimate of the difference in the numbers of apples with blemishes (golden delicious minus red delicious) at a 98 percent level of confidence?A. (–0.076,0.236)B. (–0.105,0.265)C. (–10.5,26.5)D. (–76,236)E. (−105,265)
Mathematics
1 answer:
Delvig [45]2 years ago
4 0

Answer:

98% confidence interval is (-0.105 , 0.265)

Step-by-step explanation:

n1 = 75          n2 = 75

X1 = 48          X2 = 42

P1 = X1/N1 = 0.64          P2 = X2/N2   = 0.56

98% confidence interval for difference between two proportions is :

P1 - P2  <u>+</u>   Z \sqrt{P1 (1-P1)/n1  + P2 (1-P2)/n1}

= 0.08 <u>+</u> 0.185

= (-0.105 , 0.265)

98% confidence interval is (-0.105 , 0.265)

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142 pages

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and P(B) = probability of occurrence of event B

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Thus, P(A)= Probability that Sarah scores more than 175 = 0.4

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(b).

When the occurrence of one event say A affects the occurrence of another event say B, than the two events are said to be dependent such that;

\\  &#10;P(A\cap B)=P(A)\times P(B\setminus A)\\

Now, let event A = Sarah scores more than 175

and event B = Thomas scores more than 175

Thus, P(A)= Probability that Sarah scores more than 175 = 0.4

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and P(B|A) = Sarah scores more than Thomas given that Thomas scores more than 175 = 0.3

Thus, the required probability is calculated as follows;

\\  &#10;P(A\cap B)=P(A)\times P(B\setminus A)\\  &#10;P(A\cap B)=0.2\times 0.3=0.06



             



             


7 0
1 year ago
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