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2 years ago

Find the value of X (5x+4)°+(8x-71)°

Mathematics

1 answer:

NikAS [45]2 years ago

5 0

Answer:

x = -4/5

Step-by-step explanation:

Solve for x:

(5 x + 4) (8 x - 71) = 0

Split into two equations:

5 x + 4 = 0 or 8 x - 71 = 0

Subtract 4 from both sides:

5 x = -4 or 8 x - 71 = 0

Divide both sides by 5:

x = -4/5 or 8 x - 71 = 0

Add 71 to both sides:

x = -4/5 or 8 x = 71

Divide both sides by 8:

Answer: x = -4/5 or x = 71/8

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2 years ago

How much would Carol have to invest today at 6.2% compounded annually to have $4600 for a vacation to China in two years?

KiRa [710]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4600\\
P=\textit{original amount deposited}\\
r=rate\to 6.2\%\to \frac{6.2}{100}\to &0.062\\
n=
\begin{array}{llll}
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\textit{annually, so once}
\end{array}\to &1\\

t=years\to &2
\end{cases}
\\\\\\
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2 years ago

The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act

stealth61 [152]

Answer: 0.2551

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ.

Significance level : $\alpha=1-0.95=0.05$

The critical z-value for 95% confidence : $z_{\alpha/2}=1.960$ (1)

Since , $z=\dfrac{x-\mu}{\sigma}$ (where x be any random variable that represents the temperature reading from a thermocouple.)

Then, from (1)

$\dfrac{x-\mu}{\sigma}=1.96\\\\ x-\mu=1.96\sigma$ (2)

Also, all readings are within 0.5° of μ,

i.e. $x-\mu$

i.e. $1.96\sigma$ [From (2)]

i.e. $\sigma$

i.e. $\sigma\approx0.2551$

The required standard deviation : $\sigma=0.2551$

3 0

2 years ago

Write an expression that evaluates to true if the int associated with number_of_prizes is divisible (with no remainder) by the i

hodyreva [135]

We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.

Let us assume number of Prizes are = p and

Number of participants = n.

If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.

Let us assume that quotent is taken by q.

So, we can setup an expression now.

Let us rephrase the statement .

" Number of Prizes ÷ Number of participants = quotient".

p ÷ n = q.

In fraction form we can write

p/n =q ; n ≠ 0.

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2 years ago