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GrogVix [38]
2 years ago
15

Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U

Mathematics
1 answer:
lawyer [7]2 years ago
5 0

Answer:

m∠U = 103° and m∠TRS = 6°

Step-by-step explanation:

In the given circle O,

Since, RS║VU, and VR is a transverse,

Therefor, m∠V + m∠R = 180° [Consecutive interior angles]

m∠R + 103° = 180° [m∠R = 103° given]

m∠R = 180° - 103°

m∠R = 77°

Since m∠R = m∠VRT + m∠TRS

77° = 71° + m∠TRS

m∠TRS = 77° - 71° = 6°

Quadrilateral RTUV is a cyclic quadrilateral.

Therefore, m∠U + m∠R = 180°

m∠U + 77° = 180°

m∠U = 180° - 77° = 103°

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Answer:

7 pages

Step-by-step explanation:

Given the total number of pages in the book are 16

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Let the number of pages left out to read be x

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8 0
2 years ago
Which equation is y=6x^2+12-10 rewritten in vertex form
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The formula in order to obtain the vertex form of a quadratic equation is given as 

y=a(x-h)^2+k where (h,k) is the vertex of the quadratic equation which is parabolic in shape and it is opening upward.

As given in the problem, y=6x^2+12x-10

Using the formula, we can transformed the quadratic equation y=6x^2+12x-10 into its vertex form:

y=6x^2+12x-10

<span>y= (6x^2+12x)-10    (grouping)</span>

y=6(x^2+2x)-10 (factoring Common terms per group)

y=6(x^2+2x+1)-10-6 (Completing the squares)

<span>y=6(x+1)^2-16    (Factor and Simplify) </span>

 

Hence, the vertex form of y=<span>6x^2+12x-10 is y=6(x+1)^2-16</span>

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2 years ago
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Let x be the length.
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We know that

[surface area ]=2*[area of the base]+[perimeter of the base]*height
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the answer is
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