Answer:
b) $640
Step-by-step explanation:
Competitor's price = $800
<u>Price, 20% below of competitor's:</u>
- $800 - 20% =
- $800*(100-20)/100 =
- $800*0.8 =
- $640
Correct answer choice is b) $640
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
Answer:
3x^2 + 8
Step-by-step explanation:
Given functions,
f(x) = 3x + 8 ----(1)
g(x) = x^2 -----(2)
Since,
(fog)(x) = f( g(x) ) ( Composition of functions )
=f(x^2) ( From equation (2) )
=3x^2 + 8 ( From equation (1) )
Hence,
(fog)(x)=3x^2 + 8
Step-by-step explanation:
Mrs. Smythe = x
Daughter = y
x = 2y
(x - 10) + (y - 10) = 46
x - 10 + y - 10 = 46
x + y - 20 = 46
x + y = 66
Put 2y in for x
2y + y = 66
3y = 66
y = 66/3
y = 22
The daughter is 22
The mother = 44
Answer:
181 million km
Step-by-step explanation:
"Correct to the nearest unit" means the actual value might be 1/2 unit larger (or smaller) than the reported value.
The upper bound would be the product of the maximum number of bicycles and the maximum distance each travels:
(72.5 · 10^6 bicycles)(2.5 km/bicycle) = 181.25 · 10^6 km
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Since the given numbers are good to 2 significant figures (or so), we might reasonably put the upper bound as 180·10^6 km.
