The band leader is recording the number of students in the seventh and eighth grades who play flute and clarinet. Which describe
2 answers:
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Answer:
4.979044478499338 × 10²⁶
Step-by-step explanation:
Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.
Combination factorial is define by ⁿCr =
21 group of mice receiving Drug A can be selected in ⁶⁰C₂₁ =
(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug
Drug B 21 mice can be chosen with ³⁹C₂₁ =
( 39 - 21 = 18) remained for control with ¹⁸C₁₈ =
The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = ×
×
= 4.979044478499338 × 10²⁶
Answer:
There is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 300
p = 5% = 0.05
Alpha, α = 0.05
Number of dead pixels , x = 24
First, we design the null and the alternate hypothesis
This is a one-tailed(right) test.
Formula:
Putting the values, we get,
Now, we calculate the p-value from excel.
P-value = 0.00856
Since the p-value is smaller than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Conclusion:
Thus, there is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.
Answer:
we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years
Step-by-step explanation:
Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.
Let X be the group married less than 2 years and Y less than 5 years
X Y Total
Sample size 300 300 600
Favouring 240 288 528
p 0.8 0.96 0.88
p difference = -0.16
Std error for difference =
Test statistic = p difference/std error=-6.03
p value <0.000001
Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years