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labwork [276]
2 years ago
10

How close are a meter and a yard? Convert, 1 meter into yards by using the fact that there are 100 centimeters in a meter, 2.54

centimeters in an inch, 12 inches in a foot, and 3 feet in a yard. Round your answer to the nearest tenth of a yard
Mathematics
1 answer:
Sveta_85 [38]2 years ago
5 0

Answer:

To convert 1 meter into yards

Using the given facts : 100 centimeters in a meter, 2.54 centimeters in an inch, 12 inches in a foot, and 3 feet in a yard.

we can write these as;

1 m = 100 cm

1 inches = 2.54 cm

1 ft = 12 inches and

1 yard = 3 ft

1 ft = 12 inches

3 ft = 3 \times 12 = 36 inches

Since,

1 inches  = 2.54 cm

36 inches = 91.44 cm

Also,

1 m = 100 cm

or

1 cm = \frac{1}{100} m

then;

91.44 cm = \frac{91.44}{100} =0.9144 m

⇒ 1 yards = 0.9144 m

Divide both sides by 0.9144 we get;

1 meter = \frac{1}{0.9144} = 1.0936133 yards.

Therefore, the answer is, 1 m =  1.1 yards (nearest to tenth)


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Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who
padilas [110]

Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

P_{AA} = 0.13(0.47) = 0.0611

The probability that the student also earned an A on the midterm is

P = \frac{P_{AA}}{P_{A}} = \frac{0.0611}{0.1568} = 0.3897

There is a 38.97% probability that this student earned an A on the midterm.

5 0
2 years ago
The table shows data from Vicente's Form 1040. Gross income $75,000 Standard deduction $12,000 Taxable income $63,000 Total inco
Iteru [2.4K]
The answer is a+b+c = d it’s is equivalent to a and d
7 1
2 years ago
Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
1 year ago
For questions 2-5, the number of pieces in a regular bag of Skittles is approximately normally distributed with a mean of 38.4 a
aleksley [76]

Answer:

a. -1.60377

b. 0.25451

c. 0.344

d. Option b) 78th

Step-by-step explanation:

The number of pieces in a regular bag of Skittles is approximately normally distributed with a mean of 38.4 and a standard deviation of 2.12.

a)What is the z-score value of a randomly selected bag of Skittles that has 35 Skittles? a) 1.62 b) -1.62 c) 3.40 d) -3.40 e)1.303.

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

z = 35 - 38.4/2.12

= -1.60377

Option b) -1.62 is correct

b) What is the probability that a randomly selected bag of Skittles has at least 37 Skittles? a) .152 b) .247 c) .253 d).747e).7534. .

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

z = (37 - 38.4)/2.12

= -0.66038

P-value from Z-Table:

P(x<37) = 0.25451

The probability that a randomly selected bag of Skittles has at least 37 Skittles is 0.25451

Option c) .253 is.correct

c) What is the probability that a randomly selected bag of Skittles has between 39 and 42 Skittles? a) .112 b) .232 c) .344 d).457 e).6125.

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

For 39 Skittles

z = (39 - 38.4)/2.12

= 0.28302

Probability value from Z-Table:

P(x = 39) = 0.61142

For 42 Skittles

z = (42 - 38.4)/2.12

= 1.69811

Probability value from Z-Table:

P(x = 42) = 0.95526

The probability that a randomly selected bag of Skittles has between 39 and 42 Skittles is:

P(x = 42) - P(x = 39

0.95526 - 0.61142

0.34384

= 0.344

Option c is.correct

d) What is the percentile rank of a randomly selected bag of Skittles that has 40 Skittles in it? a)82nd b) 78th c) 75th d)25th e)22nd

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

z = (40 - 38.4)/2.12

= 0.75472

P-value from Z-Table:

P(x = 40) = 0.77479

Converting to percentage = 0.77479× 100

= 77. 479%

≈ 77.5

Percentile rank = 78th

7 0
2 years ago
A rectangular prism has a length of 114 centimeters, a width of 4 centimeters, and a height of 314 centimeters.
algol13
Hello!
----------
The volume of the prism is 143184 cm^3
----------
WORK: 114*4=456*314=143184
----------
Have a great day!
4 0
2 years ago
Read 2 more answers
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