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1 year ago

14

Mitchell travels from the US to Canada, where he exchanges 150 US dollars for Canadian dollars. He then spends 20 Canadian dolla

rs, returns to the US, and exchanges the remaining money back to US dollars. How many US dollars does Mitchell have remaining?

2 answers:

Katarina [22]1 year ago

8 0

Answer:C 130.66

Step-bcc-step explanation:

lora16 [44]1 year ago

3 0

Their money rate is the same as ours so $150- 20= $ !30

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Two quadrilaterals are congruent. One has vertices P, N, O, and M, and the other has vertices S, T, V, and U. These correspondin

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Answer: $NPOM \cong VUTS$ and $OPNM \cong TVUS$ will be correct.

Explanation:

Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent, where, OM is congruent or equal to TS and $\angle P\cong \angle U$ .

in quadrilaterals NPOM and VUTS-

since, the condition $\angle P = \angle U$

and, side UV=side OM follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

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we can understand it by making the figures.

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1 year ago

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8 to 12, or if simplified, 2 to 3

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1 year ago

Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord

andrew-mc [135]

Consider the circle with center X, as shown in the figure.

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is

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2 years ago

Meeting at least one person with the flu in thirteen random encounters on campus when the infection rate is 2% (2 in 100 people

s344n2d4d5 [400]

Answer:

23.1% probability of meeting at least one person with the flu

Step-by-step explanation:

For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Infection rate of 2%

This means that $p = 0.02$

Thirteen random encounters

This means that $n = 13$

Probability of meeting at least one person with the flu

Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{13,0}.(0.02)^{0}.(0.98)^{13} = 0.7690$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.769 = 0.231$

23.1% probability of meeting at least one person with the flu

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2 years ago