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1 year ago

Sam's Furniture Store places the following advertisement in the local

Mathematics

1 answer:

Dmitry [639]1 year ago

8 0

Answer:

1. The system of equations is given as follows;

S + L = $1,300................(1)

S + 2·C = $1,400............(2)

S + L + C = $1,600.........(3)

Where;

S = The cost of a sofa

L = The cost of a love sea

C = The cost of a single chair

2. The cost of a love sea, L is $500

Step-by-step explanation:

1. The given information are;

The price of sofa and love sea = $1,300

The price of sofa and two chairs = $1,400

The price of sofa, love sea, and one chair = $1,600

Let the cost of a sofa = S

Let the cost of a love sea = L

Let the cost of a chair = C

Therefore, we have;

S + L = $1,300................(1)

S + 2·C = $1,400............(2)

S + L + C = $1,600.........(3)

2. From equation (1), we have;

L = $1,300 - S

Similarly, from equation (2),we have;

C = ($1,400 - S)/2

Substituting the values of L and C in equation (3), we have;

S + $1,300 - S + ($1,400 - S)/2 = $1,600

Which gives;

($1,400 - S)/2 = $1,600 - $1,300 = $300

$1,400 - S = 2 × $300 = $600

$1,400 = $600 + S

$600 + S = $1,400

S = $1,400 - $600 = $800

S = $800

The cost of a love seat, L, is given from the relation L = $1,300 - S, above, which gives;

L = $1,300 - $800 = $500

The cost of a love sea, L is $500 .

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<h3 /><h3>Explanation: </h3>

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2 years ago

In Boston taxicabs charge an initial fare and an additional amount for every mile traveled. Tahira is having trouble figuring ou

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Answer:

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Step-by-step explanation:

We are given the following in the question:

Let x be the initial taxicab fare and y be the additional amount for every mile traveled.

Cost for a two mile ride = $7.00

Thus, we can write the equation:

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Thus, we can write the equation,

$x + 9y = 24.50$

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$x + 9y - (x + 2y) = 24.50 - 7\\7y = 17.5\\y = 2.5\\\Rightarrow x + 2(2.5) = 7\\x = 2$

Thus, $2 is the initial fare and $2.5 is the cost for every mile traveled.

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1 year ago

A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

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Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

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We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

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1 year ago

A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

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Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

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For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

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2 years ago

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vivado [14]

Answer:

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