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kherson [118]
2 years ago
12

An account with $250 balance accrues 2% annually. If no deposits or withdrawals are made, which graphs can be used to determine

approximately how many years will it take for the balance to be $282?

Mathematics
1 answer:
butalik [34]2 years ago
4 0

Answer:

Here we have an exponential growth, where the rate of growth is 2% or 1.02, and the initial value is $250.

Then we can write this as:

M(y) = $250*(1.02)^y

where y is the number of years and M is the amount of money.

the graph of this equation will help you to find the number of years needed to have $282 in the account, but we can solve it also only with math.

M(y) = $282 = $250*(1.02)^y

         $282/$250 = 1.02^y

          1.128 = 1.02^y

          ln(1.128)/ln(1.02) = y = 6.08

So the graph is correct.

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I think about 52 bags
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The perimeter of a rectangle is 343434 units. Its width is 6.56.56, point, 5 units.
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This is annoying


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ok.
perimiter=2(Length+Width)
P=2(L+W)
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distribute
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2 years ago
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What is the y-intercept of line MN?<br><br> What is the equation of MN written in standard form?
bagirrra123 [75]

Answer:

y-intercept of the line MN = 2

Standard form of the equation ⇒ x + y = 2

Step-by-step explanation:

Coordinates of the ends of a line MN → M(-3, 5) and N(2, 0)

Slope of a line = \frac{y_2-y_1}{x_2-x_1}

                        = \frac{5-0}{-3-2}

                        = -1

Equation of the line MN passing through (-3, 5) and slope = -1,

y - 5 = (-1)(x + 3)

y - 5 = -x - 3

y = -x + 2

This equation is in the y-intercept form,

y = mx + b

where m = slope of the line

b = y-intercept

Therefore, y-intercept of the line MN = 2

Equation in the standard form,

x + y = 2

8 0
2 years ago
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A 16.0-inch chord is drawn in a circle whose radius is 10.0 inches. what is the angular size of the minor arc of this chord? wha
statuscvo [17]
PART I
Angular size of the minor arc . 
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Therefore, using trigonometric ratio, sine = opp/hyp
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PART II
The length of an arc is given by (θ/360 )× 2πr
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8 0
2 years ago
A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 Miles. What
MakcuM [25]

Answer:

The actual area 21600 miles²

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- A drawing that shows a real object with accurate sizes reduced or

 enlarged by a certain amount called the scale

- Drawing scale is a ratio between the drawing length and the

 actual length

- To find the actual dimensions from the drawing dimensions use the

  scale drawing

*<em> Lets solve the problem</em>

- A map of a rectangular park has a length of 4 inches and a width

 of 6 inches

∴ The drawing dimensions are:

# length = 4 inches

# width = 6 inches

- The scale of the map is 1 inch foe every 30 miles

∴ The scale drawing is 1 : 30

- To find the actual area find the actual dimensions

∵ The scale drawing is 1 : 30

∵ The length = 4 inches and the width = 6 inches

- By using cross multiplication

∴  1        :        30

   4       :  actual length

   6       :  actual width

∴ Actual length = (4 × 30)/1 = 120

∴ Actual length = 120 miles

∴ Actual width = (6 × 30)/1 = 180

∴ Actual Width = 180 miles

∴ The actual dimensions are 120 miles and 180 miles

∵ The area of any rectangle = length × width

∴ The actual area = 120 × 180 = 21600

∴ The actual area 21600 miles²

5 0
2 years ago
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