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sattari [20]
2 years ago
7

1. Formulate 500 lbs of a 21% CP ration using Soybean Meal (44% CP) and Corn (9% CP).

Mathematics
1 answer:
zmey [24]2 years ago
3 0

Answer:

Step-by-step explanation:

see sketch below

1 Formulate 500 lbs of a 21% cp ration using soybean meal( 44% cp) and corn (9% cp)

How many pounds of soybean meal will be used?

12 parts soy bean meal/ 35 parts total = 0.34 parts from soy bean meal

0.34 parts from soy bean meal X 500 lbs ration = 170 lbs soy bean meal

How many pounds of corn will be used ?

23 parts corn / 35 parts total = 0.66 parts from corn

0.66 parts from corn x 500 lbs ration = 330 lbs corn needed

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the map below shows the location of 3 houses where you had to do lawn work today. Your truck gets 8 miles per gallon of gasoline
sergiy2304 [10]

Answer:

the answer is 3.80 cents

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Triangle MNO is an equilateral triangle with sides measuring 16 StartRoot 3 EndRoot units. Triangle M N O is an equilateral tria
Lesechka [4]

Answer:

The correct option is second one i.e 24 units.

Therefore the height of the triangle is

NR=24\ units

Step-by-step explanation:

Given:

An equilateral triangle has all sides equal.

ΔMNO is an Equilateral Triangle with sides measuring,

NM = MO = ON =16\sqrt{3}

NR is perpendicular bisector to MO such that

MR=RO=\dfrac{MO}{2}=\dfrac{16\sqrt{3}}{2}=8\sqrt{3} .NR ⊥ Bisector.

To Find:

Height of the triangle = NR = ?

Solution :

Now we have a right angled triangle NRM at ∠R =90°,

So by applying Pythagoras theorem we get

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting the values we get

(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units

Therefore the height of the triangle is

NR=24\ units

6 0
2 years ago
Read 2 more answers
Round 4.265 to the nearest hundredth
jekas [21]
4.265 rounded to the nearest hundredth is 4.27
3 0
2 years ago
Allie has two cars- a truck and a sedan. Last week, she used 3 gallons of gas in the truck and 5 gallons of gas in the sedan and
gavmur [86]

Answer:

sedan = 26 miles/gallon

truck = 17 miles/gallon

Step-by-step explanation:

try to write the text in mathematical format as a system of equations

t=truck s=sedan

\left \{ {{3t+5s=181} \atop {7t+6s=275}} \right.

first equation can be written as

t= (181-5s)/3

we can use it in the second equation and rewrite it as

7[(181-5s)/3]+6s = 275

7(181/3 -5/3s) + 6s = 275

1267/3 - 35/3s + 6s = 275

-35/3s + 18/3s = 275-1267/3

-35/3s + 18/3s = 825/3 - 1267/3

-35s + 18s = 825 -1267

-17s = -442     s = 442/17 = 26 sedan has an average of 26 miles/gallon

we use this value of s in the first equation

3t + 5*26=181      3t=181-130   t= 51/3 = 17 truck has an average of 17 miles/gallon

5 0
2 years ago
Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. Be sure to create and name
sattari [20]

Answer:

Given: A triangle ABC and a line DE parallel to BC.

To prove: A line parallel to one side of a triangle divides the other two sides proportionally.

Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have

∠A=∠A (Common)

∠ADE=∠ABC (Corresponding angles)

Thus, by AA similarity, ΔABC is similar to ΔADE, therefore

AB/AD= AC/AE

⇒AD+DB/AD = AE+EC/AE

⇒1+DB/AD = 1+ EC/AE

⇒DB/AD = EC/AE

Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.

⇒Therefore Proved

Hope this helps!!!

3 0
2 years ago
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