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1 year ago

1. Formulate 500 lbs of a 21% CP ration using Soybean Meal (44% CP) and Corn (9% CP).

Mathematics

1 answer:

zmey [24]1 year ago

3 0

Answer:

Step-by-step explanation:

see sketch below

1 Formulate 500 lbs of a 21% cp ration using soybean meal( 44% cp) and corn (9% cp)

How many pounds of soybean meal will be used?

12 parts soy bean meal/ 35 parts total = 0.34 parts from soy bean meal

0.34 parts from soy bean meal X 500 lbs ration = 170 lbs soy bean meal

How many pounds of corn will be used ?

23 parts corn / 35 parts total = 0.66 parts from corn

0.66 parts from corn x 500 lbs ration = 330 lbs corn needed

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Show that A(t)=300−250e0.2−0.02t satisfies the differential equation ⅆAⅆt=6−0.02A with initial condition A(10)=50 .

Elina [12.6K]

Step-by-step explanation:

dA/dt = 6 − 0.02A

dA/dt = -0.02 (A − 300)

Separate the variables.

dA / (A − 300) = -0.02 dt

Integrate.

ln(A − 300) = -0.02t + C

Solve for A.

A − 300 = Ce^(-0.02t)

A = 300 + Ce^(-0.02t)

Use initial condition to find C.

50 = 300 + Ce^(-0.02 × 10)

50 = 300 + Ce^(-0.2)

-250 = Ce^(-0.2)

C = -250e^(0.2)

A = 300 − 250e^(0.2) e^(-0.02t)

A = 300 − 250e^(0.2 − 0.02t)

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2 years ago

Mai bought eleven 12-ounce bags of

ella [17]

Answer:

8.25 pounds

Step-by-step explanation:

When you multiply 12 and 11 you get 132. So then you would have to divided the total amount of ounces by 16 to get the amount of pounds

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1 year ago

A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful

Tems11 [23]

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

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1 year ago

Last Saturday they were 1486 people at the Cineplex. There were about the same number of people in each of the six theaters. Bet

padilas [110]

When you do 1486x6 it equals 8,916

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1 year ago

. En un concesionario de coches hay modelos de varios colores. Los rojos suponen 1 6 del total, los azules, 2 9 del total, y los

Sholpan [36]

Complete question :

En un concesionario de coches hay modelos de varios colores. Los rojos suponen 1/6 del total, los azules, 2/9 del total, y los blancos, 4/15 del total.

a)¿Cuál de esos colores es el más frecuente?

b) Si hay 40 coches azules, ¿cuántos hay en total?

Responder:

Coches blancos

180 coches

Explicación paso a paso:

Dado que:

Rojo = 1/6 del total

Azul = 2/9 del total

Blanco = 4/15 del total

Para determinar qué color es el más alto, convierta los valores en decimal:

1/6 = 0,166667

2/9 = 0,2222

15/4 = 0,26667

Por lo tanto;

4/15> 2/9> 1/6

Por tanto, los coches blancos son los que más

2.)

Sea Número total = x

Por lo tanto,

2/9 de x = 40

2x / 9 = 40

2x = 360

x = 180

Por tanto, hay 180 coches en total.

4 0

1 year ago