In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. A long-distance telephone c
1 answer:
Answer:
We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.
The correct system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
So then the best option for this case would be:
H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes
Step-by-step explanation:
We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.
The correct system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
So then the best option for this case would be:
H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes
And in order to test the hypothesis we can use a one sample t test or z test depending if we know the population deviation or not
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that simply means, 3 circles with a radius of 3, overlapping the triangle
now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors
hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle
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so
you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format
each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle
now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors
hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle
so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3
so
you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format
<u>Given</u>:
Given that a circle O with two tangents BA and BC.
The major arc AC is 234°
The minor arc AC is 126°
We need to determine the measure of ∠ABC
<u>Measure of ∠ABC:</u>
We know the property that, "if a tangent and a secant, two tangents or two secants intersect in the interior of the circle, then the measure of angle formed is one half the difference of the measures of the intercepted arcs."
Hence, applying the above property, we have;
Substituting the values, we get;
Thus, the measure of ∠ABC is 54°
Hence, Option b is the correct answer.