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Dvinal [7]
2 years ago
7

In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. A long-distance telephone c

ompany wants to perform a hypothesis test to determine whether the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes. H0: μ < 7.2 minutes Ha: μ > 7.2 minutes H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes H0: μ = 7.2 minutes Ha: μ ≤ 7.2 minutes H0: μ ≠ 7.2 minutes Ha: μ = 7.2 minutes
Mathematics
1 answer:
scoundrel [369]2 years ago
4 0

Answer:

We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.

The correct system of hypothesis are:

Null hypothesis: \mu =7.2

Alternative hypothesis: \mu \neq 7.2

So then the best option for this case would be:

H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes

Step-by-step explanation:

We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.

The correct system of hypothesis are:

Null hypothesis: \mu =7.2

Alternative hypothesis: \mu \neq 7.2

So then the best option for this case would be:

H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes

And in order to test the hypothesis we can use a one sample t test or z test depending if we know the population deviation or not

You might be interested in
A local Dominos sold a total of 1600 small pizzas ($9) and pasta dinners ($13) during the Super Bowl. How many of each did Domin
vitfil [10]
S=small pizzas
p=pasta dinners

s+p=1600

9s+13p=15600
multiply first equaiton by -9 and add to the second one

-9s-9p=-14400
<u>9s+13p=15600 +</u>
0s+4p=1200

4p=1200
divide by 4
p=300

sub back

s+p=1600
s+300=1600
minus 300 both sides
s=1300

1300 small pizzas
300 pasta dinners
5 0
2 years ago
A snowboarder leaves an 8-foot-tall ramp with an upward velocity of 28 feet per second. The function h   16t 2  28t 8 gives
mr_godi [17]

The complete question is;

A snowboarder leaves an 8-foot-tall ramp with an upward velocity of 28 feet per second. The function h = -16t² + 28t + 8 gives the height h (in feet) of the snowboarder after t seconds. The snowboarder earns 1 point per foot of the maximum height reached, 5 points per second in the air, and 25 points for a perfect landing. With a perfect landing, how many total points does the snowboarder receive?

Answer:

Total points earned with a perfect landing = 111 points

Step-by-step explanation:

First of all, let's find the maximum height of the given parabolic function h = -16t² + 28t + 8

h_max = c - (b²/4a)

where: a = -16, b = 28, c = 8

h_max = 8² - 28²/(4*(-16))

h_max = 64 + 784/64

h max = 76.25 ft ≈ 76 ft

The question says that the snowboarder earns 1 point per foot of the maximum height reached.

Thus, the points from the maximum height reached are 76 points

Now, let's find the maximum time in air by solving the equation for h = 0 Thus;

-16t² + 28t +8 = 0

Using quadratic formula,

t = [-28 ± √(28² - (4*-16*8))]/(2*-16)

t = 2 or -0.25

We'll use 2 as we are looking for maximum time.

The question says at maximum time, it's 5 points for each second in the air,

thus, points for seconds in air = 5 × 2 = 10 points

We are told 25 points for perfect landing.

Thus,

Total points earned with a perfect landing = 76 + 10 + 25 = 111 points

7 0
2 years ago
An episode of the television show, Legend of the Far Mountain, normally lasts 30 minutes and has 8 minutes of commercials. Tonig
gizmo_the_mogwai [7]
U give to me a very hard question, I dont know
6 0
2 years ago
Read 2 more answers
A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports
hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

t  =  3.054

4

The p-value  is   p-value  =  P(Z >  3.054) = 0.0011291

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1  =  51

    The first sample  mean is \mu_1  =  36

    The second sample size is  n_2  =  41

    The second sample  size is  \mu_2  =  25

     The first standard deviation is  \sigma _1  =  21.4 \  g

    The second standard deviation is  \sigma _2  =  12.8 \  g

  The  level of significance is  \alpha =  0.05

The  null hypothesis is  H_o  :  \mu_1 = \mu_ 2

The  alternative hypothesis is  H_a :  \mu_1 > \mu_2

Generally the test statistics is mathematically represented as

    t  =  \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1}  + \frac{s_2^2}{n_2}  } }

=>   t  =  \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51}  + \frac{ 12.8^2}{41}  } }

=> t  =  3.054

The  p-value is mathematically represented as

     p-value  =  P(Z >  3.054)

Generally from the z table  

             P(Z >  3.054) =  0.0011291

=>   p-value  =  P(Z >  3.054) = 0.0011291

From the values obtained  we see that p-value  < \alpha so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0
2 years ago
Which graph represents the solution set for the inequality StartFraction one-half EndFraction x is less than or equal to 18.x ≤
Mrrafil [7]

Answer:

A number line from 0 to 60 in increments of 6. A point is at 36 and a bold line starts at 36 and is pointing to the left. ⇒ last answer

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- <u><em>When solving an inequality, there are some important points:</em></u>

# If the inequality is x > a, then it represented on the number line by

  a ray with empty small circle as end starts at a and pointed to

  the right (⇒ ∞)

# If the inequality is x ≥ a, then it represented on the number line by

  a ray with bold small circle as end starts at a and pointed to the

  right (⇒ ∞)

# If the inequality is x < a, then it represented on the number line

  by a ray with empty small circle as end starts at a and pointed to

  the left (⇒ -∞)

# If the inequality is x ≤ a, then it represented on the number line by

  a ray with bold small circle as end starts at a and pointed to the

  left (⇒ -∞)

* <em>Lets solve the problem</em>

∵ 1/2 x ≤ 18

- Multiply both sides by 2

∴ x ≤ 36

- To represent it draw a number line from 0 to 60 and the counted

 by 6 as 0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

- Draw a ray with bold end starts at 36 and pointed to the left

∴ A number line from 0 to 60 in increments of 6. A point is at 36 and

  a bold line starts at 36 and is pointing to the left.

3 0
2 years ago
Read 2 more answers
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