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andreyandreev [35.5K]
2 years ago
10

The data below are the final exam scores of 10 randomly selected statistics students and the number of hours they studied for th

e exam. What is the best predicted value for y given x = 7? Assume that the variables x and y have a significant correlation.
Hours, x 3 5 2 8 2 4 4 5 6 3
Scores, y 65 80 60 88 66 78 85 90 90 71
Choose one answer.

A. 89
B. 90
C. 91
D. 92
Mathematics
1 answer:
laiz [17]2 years ago
4 0

Answer:

Correct option: (C) 91.

Step-by-step explanation:

To predict the score received by a student if the number of hours studied is 7 can be done using a regression line.

The general form of a regression line is:

y=\alpha +\beta x

Here,

<em>Y</em> = dependent variable

<em>X</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

The formula to compute the slope and intercept are:

\alpha =\frac{\sum Y.\sum X^{2}-\sum X\sum XY}{n.\sum X^{2}-(\sum X)^{2}}

\beta=\frac{n.\sum XY-\sum X\sum Y}{n.\sum X^{2}-(\sum X)^{2}}

Consider the table below.

Compute the value of <em>α</em> as follows:

\alpha =\frac{\sum Y.\sum X^{2}-\sum X\sum XY}{n.\sum X^{2}-(\sum X)^{2}}=\frac{(773\times 208)-(42\times 3406)}{(10\times 208)-(42)^{2}}=56.114

Compute the value of <em>β</em> as follows:

\beta=\frac{n.\sum XY-\sum X\sum Y}{n.\sum X^{2}-(\sum X)^{2}}=\frac{(10\times 3406)-(42\times 773)}{(10\times 208)-(42)^{2}}=5.044

The regression equation is:

y=56.114+5.044\ x

For <em>x</em> = 7 compute the value of <em>y</em> as follows:

y=56.114+5.004\ x\\=56.114+(5.044\times 7)\\=91.422\\\approx 91

Thus, the score received by a student who studied 7 hours is 91.

The correct option is (C).

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we know that

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then

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therefore

<u>the answer is</u>

the measure of x is 18° and the measure of y is 29°


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