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Andru [333]
2 years ago
11

N 1928, when the high jump was first introduced as a women's sport at the Olympic Games, the winning jump for women was 70.0 inc

hes, while the winning jump for men was 86.5 inches. Since then, the winning jump for women has increased by about 0.48% per year, while the winning jump for men has increased at a slower rate, 0.4%. If these rates continue, when will the winning jump for women be higher than the winning jump for men?
Mathematics
1 answer:
n200080 [17]2 years ago
4 0
Omg ! I’m not sure at all
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Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then
nekit [7.7K]

Answer: The field F has a continuous partial derivative on R.

Step-by-step explanation:

For the field F has a continuous partial derivative on R, fxy must be equal to fyx and since our field F is ∇f,

∇f = fxi + fyj + fzk.

Comparing the field F to ∇f since they at equal, P = fx, Q = fy and R = fz

Since P is fx therefore;

∂P ∂y = ∂ ∂y( ∂f ∂x) = ∂2f ∂y∂x

Similarly,

Since Q is fy therefore;

∂Q ∂x = ∂ ∂x( ∂f ∂y) = ∂2f ∂x∂y

Which shows that ∂P ∂y = ∂Q ∂x

The same is also true for the remaining conditions given

4 0
1 year ago
A woman who is 64 inches tall has a shoulder width of 16 inches. How tall is a woman who has a shoulder width of 18.5 inches?
mel-nik [20]
If we turn this to a ratio we get 64:16 and we need ?:18.5. To easily solve this we would divide 64 by 16 and 64/16= 4 now that we know that the shoulder width is 1/4 if a persons height we can then multiply 18.5 by 4 to find the woman’s height. 18.5x4=74
So your answer is 74 inches
7 0
1 year ago
Diane has a hospital appointment. When she arrives at the hospital, the car park is nearly full. There are a total of 534 car pa
nevsk [136]
Hiii

all you do is subtract...
534-476=58

58 spots are left.
6 0
1 year ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

QR=10\ units

step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

6 0
2 years ago
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Find the balance in the account. $800 principal earning 7%, compounded annually, after 4 years
scoray [572]
800×(1.07)^(4) =1,048.63
6 0
2 years ago
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