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Andru [333]
2 years ago
11

N 1928, when the high jump was first introduced as a women's sport at the Olympic Games, the winning jump for women was 70.0 inc

hes, while the winning jump for men was 86.5 inches. Since then, the winning jump for women has increased by about 0.48% per year, while the winning jump for men has increased at a slower rate, 0.4%. If these rates continue, when will the winning jump for women be higher than the winning jump for men?
Mathematics
1 answer:
n200080 [17]2 years ago
4 0
Omg ! I’m not sure at all
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The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
Usimov [2.4K]
 The answer to the question is 300 square feet
4 0
2 years ago
Rameen’s heating bill is $5.42 per month plus $1.08 per therm. How many therms can Rameen use if he wants his heating bill to be
hammer [34]

Write and solve an inequality:

Total(t) = $5.42 + ($1.08/therm)(t) ≤ $87.50.

First, subtract $5.42 from $87.50:  then ($1.08/therm)(t) ≤ $82.08

Next, divide both sides by $1.08 per therm:


t ≤ ($82.08) / ($1.08/therm) = 76 therms (maximum).  Thus, Rameen's usage could be [0,76] (therms).

3 0
2 years ago
Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect. In the kite, AC = 10 a
Oduvanchick [21]

Answer:

30 u^{2}

Step-by-step explanation:

The computation of the area of kite ABCD is shown below:

Given data

AC = 10 ;

BD = 6

As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal

Now the area of quadrilateral when the diagonals are given

So, it is

\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}

where,

d_{1}=10\ and\ d_{2}=6

So, the area of the quadrilateral is

=\frac{1}{2}(10)(6)\\\\=30 u^{2}

4 0
2 years ago
Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
1 year ago
Washington is 44 miles south of Lawrence. and midland is 63 miles east of Lawrence. how far apart are Washington and midland?
gregori [183]
The answer is 21 miles
3 0
2 years ago
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