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ollegr [7]
2 years ago
6

The university is on a bearing of 050 degrees from the stadium and 300 degrees from the hospital. Mark the position of the unive

rsity on the map with a cross

Mathematics
1 answer:
Licemer1 [7]2 years ago
6 0

Answer:

Check Explanation

Step-by-step explanation:

The map isn't available, but, one can draw this bearings with the descriptions given

Angles for bearings are usually drawn, reading from the north direction.

A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.

For the sketch on the map.

On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.

Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.

Wherever the line from the hospital meets the line from the stadium, is where the University is located.

Hope this Helps!!!!

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A business school professor uses multiple choice tests. Each question on his exams has five possible answers which are assumed t
avanturin [10]

Answer:

a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution

b. The degrees of freedom do you have for this test is 4

c.  The calculated value of the test statistic is 9.250

Step-by-step explanation:

a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.

b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:

degrees of freedom=k-1

degrees of freedom=5-1

degrees of freedom=4

c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:

expected frecuency=total observed frecuency/total number of category

expected frecuency=1,000/5

expected frecuency=200

Hence, to calculate the value of the test statistic we have to calculate the following formula:

x∧2=∑(fo-fe)∧2/fe

=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2

=9.250

The calculated value of the test statistic is 9.250

7 0
2 years ago
Which expression(s) have a greatest common factor (GCF) of 3xy2 with 42xy4
Aleks [24]

Answer:

3xy2

Step-by-step explanation:

GCF is the largest  factors which are common in two or more numbers.

We find the GCF of two or more number number by breaking each number into their factor and then observe which factors are common in the group and then we multiple the common number to get the GCF.

Lets understand this by an example

GCF of 24 and 36

factors of 12 = 2*2*2*3  ,   factors of 36 = 2*2*3*3

hence we see that 2,2 and 3 are common in 12 and 36 hence

GCF will be 2*2*3 = 12

Coming back to problem

given

Expression 1 is 3xy^2

factor of 3xy^2 = 3*x*y*y

Expression 2 is 42xy4

factor of 42xy4 = 2*3*7*x*y*y*y*y

common factor between the two expressions are

3, x, y , y

hence GCF will be = 3*x*y*y =3xy2  Answer

3 0
2 years ago
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

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So f(0,0)=ln19.

8 0
2 years ago
A rectangular prism has a length of 4.2 cm, a width of 5.8 cm, and a height of 9.6 cm. A similar prism has a length of 14.7 cm,
grigory [225]

Answer: 3.5

Step-by-step explanation:

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Dimensions of smaller prism = length of 14.7 cm, a width of 20.3 cm, and a height of 33.6 cm.

Scale factor = \dfrac{\text{Size of image}}{\text{Size of original figure}}

Since, smaller figure is the original figure and the bigger one is the image.

So, scale factor = \dfrac{14.7}{4.2}=3.5  [Taking lengths

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ris is a botanist who works for a garden that many tourists visit. The function f(s) = 2s + 25 represents the number of flowers
olasank [31]

Answer:

A.  f(s) = 2s + 34

B. Mole

C. f(s) = 2s + 54

Step-by-step explanation:

A. Its a prediction  the 34 can be any number reasonably close to 25

B. Amount of substance - mole (mole)

c. f(s) = 2s + 54

3 0
2 years ago
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