Answer:
a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution
b. The degrees of freedom do you have for this test is 4
c. The calculated value of the test statistic is 9.250
Step-by-step explanation:
a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.
b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:
degrees of freedom=k-1
degrees of freedom=5-1
degrees of freedom=4
c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:
expected frecuency=total observed frecuency/total number of category
expected frecuency=1,000/5
expected frecuency=200
Hence, to calculate the value of the test statistic we have to calculate the following formula:
x∧2=∑(fo-fe)∧2/fe
=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2
=9.250
The calculated value of the test statistic is 9.250
Answer:
3xy2
Step-by-step explanation:
GCF is the largest factors which are common in two or more numbers.
We find the GCF of two or more number number by breaking each number into their factor and then observe which factors are common in the group and then we multiple the common number to get the GCF.
Lets understand this by an example
GCF of 24 and 36
factors of 12 = 2*2*2*3 , factors of 36 = 2*2*3*3
hence we see that 2,2 and 3 are common in 12 and 36 hence
GCF will be 2*2*3 = 12
Coming back to problem
given
Expression 1 is 3xy^2
factor of 3xy^2 = 3*x*y*y
Expression 2 is 42xy4
factor of 42xy4 = 2*3*7*x*y*y*y*y
common factor between the two expressions are
3, x, y , y
hence GCF will be = 3*x*y*y =3xy2 Answer
Answer:
f(0,0)=ln19
Step-by-step explanation:
is given as continuous function, so there exist
and it is equal to f(0,0).
Put x=rcosA annd y=rsinA

we know that
, so we have that


So f(0,0)=ln19.
Answer: 3.5
Step-by-step explanation:
Given: Dimensions of larger prism = length of 4.2 cm, a width of 5.8 cm, and a height of 9.6 cm.
Dimensions of smaller prism = length of 14.7 cm, a width of 20.3 cm, and a height of 33.6 cm.
Scale factor = 
Since, smaller figure is the original figure and the bigger one is the image.
So, scale factor =
[Taking lengths
Hence, the factor to produce the corresponding dimensions of the larger prism = 3.5
Answer:
A. f(s) = 2s + 34
B. Mole
C. f(s) = 2s + 54
Step-by-step explanation:
A. Its a prediction the 34 can be any number reasonably close to 25
B. Amount of substance - mole (mole)
c. f(s) = 2s + 54