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Aliun [14]
2 years ago
7

A cylindrical pressure vessel has a height of 9 feet and a diameter of 6 feet. How much gas can the pressure vessel hold when fu

ll?
Mathematics
2 answers:
stellarik [79]2 years ago
4 0
Height of the cylindrical pressure vessel = 9 feet
Diameter of the cylindrical pressure vessel = 6 feet
Then
Radius of the cylindrical pressure vessel = (6/2) feet
                                                                   = 3 feet
Then
Volume of the cylindrical pressure vessel = <span>π<span>r^2</span></span><span>h</span>
                                                                   = 3.14 * (3)^2 * 9 cubic feet
                                                                   = 3.14 * 9 * 9 cubic feet
                                                                   = 254.34 cubic feet
So the amount of gas that the cylindrical pressure vessel can hold is 254.34 cubic feet. I hope the procedure is clear enough for you to understand.
lianna [129]2 years ago
4 0

Answer:

81The majority f math problems do not multiply pi

Step-by-step explanation:

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A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume
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Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

P(W)=0.80

Then the probability that the player losses is,

P(L)=1-P(W)=1-0.80=0.20

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = 1-P(L)-P(WL)

                                    =1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64

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(c)

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The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable X\sim Bin(n=3, p=0.4096)

The probability distribution of binomial is:

P(X=x)={n\choose x}p^{x} (1-p)^{n-x}

The probability that the player defeats all the 4 opponents at least once is,

P (<em>X</em> ≥ 1) = 1 - P (<em>X</em> < 1)

             = 1 - P (<em>X</em> = 0)

             =1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942

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3 0
2 years ago
Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
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Option A

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<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

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(12x^3-2x^2)+(18x-3)

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(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

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