The perimeter of the original rectangle is:
P = 2w + 2l = 70
The area of the original rectangle is:
A = w * l = 250
Then, by modifying the length of its sides we have:
Perimeter:
P '= 2 (2w) +2 (2l)
Rewriting:
P '= 2 (2w + 2l)
P '= 2P
P '= 2 (70)
P '= 140
Area:
A '= (2w) * (2l)
Rewriting:
A '= (2) * (2) (w) * (l)
A '= 4 * w * l
A '= 4 * A
A '= 4 * 250
A '= 1000
Answer:
the new area and the new perimeter are:
P '= 140
A '= 1000
Answer:
One Angle = 110°
Other Angle = 70°
Step-by-step explanation:
A linear pair means that two angles are in a straight line (or, a straight angle).
A straight line is 180 degrees.
THey are supplementary.
We can say one angle is "a" and another one is "b".
<em>One angle is 10 MORE THAN 2/3rds of the other, we can write:</em>
<em>
</em>
<em />
<em>Also, since they are supplementary (add up to 180), we can write:</em>
<em>a + b = 180</em>
<em />
We can now substitute 1st equation in this one and find b:

Since a + b = 180, we can write:
a + 110 = 180
so,
a = 180 - 110
a = 70
Thus,
One Angle = 110°
Other Angle = 70°
Answer:
Answer: 14 feet. a. The Pythagorean theorem is a^2 + b^2 = c^2, where a and b are the sides of a right angle. By plugging in the sides of the wall, and solving for c, you can find the answer. 10^2 + 10^2 = c^2
| 100 + 100 = c^2 | 200 = c^2 | c = sqrt 200 | c = 14. The other way to solve this would be using the trig functions. You know that the angle between the hypotenuse and the wall side is 45 degrees, so you can use Sine to determine the hypotenuse. Sine is equal to opposite over hypotenuse. Sin (45) = 10/h | Sin (45) * h = 10 | h = 10/Sin (45) | h = 14. Both of the methods result in 14.
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Step-by-step explanation:
HOI!!
ok 3.5 apr is equivelent to 2.5 so your answer would be A
hope this helps!!!
:) :) :)
Answer:

Step-by-step explanation:
The calculation of the value of p minimizes is shown below:-
We will assume the probability of coming heads be p
p(H) = p
p(T) = 1 - P
Now, H and T are only outcomes of flipping a coin
So,
P(TTH) = (1 - P) = (1 - P) (1 - P) P
= (1 + P^2 - 2 P) P
= P^3 - 2P^2 + P
In order to less N,TTH
we need to increase P(TTH)
The equation will be

3P^2 - 4P + 1 = 0
(3P - 1) (P - 1) = 0
P = 1 and 1 ÷ 3
For P(TTH) to be maximum

= 6P - 4
and
(6P - 4) is negative which is for
