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Vitek1552 [10]
2 years ago
14

You remove four fuses of 10, 20, 30, and 30 amperes each, but you do not mark the corresponding circuits. If you insert the fuse

s so that each sequence is equally likely, what is the probability that the appropriate amperage fuse is assigned to all the circuits
Mathematics
1 answer:
iren2701 [21]2 years ago
4 0

Answer:

Standard amperage sizes of the Code are 15, 20, 25, 30, 35, 40, 45, 50, 60, ... Additional standard ampere ratings for fuses are 1, 3, 6, 10 and 601

Step-by-step explanation:

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The quotient of (x4 + 5x3 – 3x – 15) and a polynomial is (x3 – 3). What is the polynomial?
Sav [38]

Answer:

Step-by-step explanation: its c. x+ 5

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1 year ago
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Create a storyline (word problem) using the following algebraic expression: 1,000/r
mamaluj [8]

Answer:

Suppose there are 1,000 candies in a jar. There are 50 children in a room. If i want to share 1000 candies among all the children. How can i divide 1,000 candies equally in 50 children.

Step-by-step explanation:

Create a story line(word problem) means to create a fake or real story by translating an algebraic expression in english.

We can create a story by the given 1,000/r:

Suppose there are 1,000 candies in a jar. There are 50 children in a room. If i want to share 1000 candies among all the children. How can i divide 1,000 candies equally in 50 children.

Here r = 50....

7 0
1 year ago
Let x = 8.99999 . (a) Is x < 9 or is x = 9? x < 9 It is neither; x > 9 x = 9 x < 9 and x = 9 It cannot be determined
qaws [65]

Answer: idk

Step-by-step explanation:

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4 0
2 years ago
Learning Task 4. Multiply each of the following. Use cancellation method
astra-53 [7]

Answer:

1) 2/7

2) 8/11

3) 3/2 or 1 1/2

4) 32/35

Step-by-step explanation:

1.5/7•14/35

= 5/7 × 14/35

Using Cancellation method

= 1/1 × 2/7

= 2/7

2.[4/5][10/11]

= 4/5 × 10/11

Using Cancellation method

= 4/1 × 2/11

= 8/11

3.8 3/4 multiplied by 2/9

= 8 3/4 × 2/9

= 27/4 × 2/9

= 3/2 × 1/1

= 3/2

= 1 1/2

4. [4/5]10/11][7/8]

40/50 ÷ 77/88

= 40/50 × 88/77

= 40/50 × 8/7

= 40/25 × 4/7

= 8/5 × 4/7

= 32/35

4 0
2 years ago
Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?
irakobra [83]

First, note that m\angle A+m\angle C=90^{\circ}. Then

m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.

Consider all options:

A.

\tan A=\dfrac{\sin A}{\sin C}

By the definition,

\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.

Now

\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.

Option A is true.

B.

\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.

By the definition,

\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.

Then

\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.

Option B is false.

3.

\sin C = \dfrac{\cos A}{\tan C}.

By the definition,

\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.

Now

\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.

Option C is false.

D.

\cos A=\tan C.

By the definition,

\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.

As you can see \cos A\neq \tan C and option D is not true.

E.

\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.

By the definition,

\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.

Then

\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.

This option is false.

8 0
2 years ago
Read 2 more answers
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