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jekas [21]
1 year ago
12

The quotient of (x4 + 5x3 – 3x – 15) and a polynomial is (x3 – 3). What is the polynomial?

Mathematics
2 answers:
Sav [38]1 year ago
7 0

Answer:

Step-by-step explanation: its c. x+ 5

Marina86 [1]1 year ago
6 0

Answer:

C. x + 5

Just did test on edge, got 100%

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Timothy makes reduced copies of a photograph that has an actual length of 8 in. Each time he presses the reduce button on the co
Aleksandr-060686 [28]

Answer:

length of the photograph will be 4.2 in. after pressing the button 5 times.

Step-by-step explanation:

By pressing the button, every time size of the photograph gets reduced by 12%.

Therefore, the sequence formed by the reduced sizes of the photo will be a geometric sequence and the formula for the size of the reduced image will be,

L = l(1-\frac{12}{100})^{n}

Where l = Actual length of the photograph

L = length of the reduced image

n = Number of times the button has been pressed

For l = 8 in. and n = 5

L = 8(1-0.12)^{5}

  = 8(0.88)^{5}

  = 4.22 in

L ≈ 4.2 in.

Therefore, length of the photograph will be 4.2 in. after pressing the button 5 times.

3 0
2 years ago
Find the point (x,y) of x2+14xy+49y2=100 that is closest to the origin and lies in the first quadrant.
Gala2k [10]

Notice that

x^2+14xy+49y^2=(x+7y)^2

so the constraint is a set of two lines,

(x+7y)^2=100\implies\begin{cases}x+7y=10\\x+7y=10\end{cases}

and only the first line passes through the first quadrant.

The distance between any point (x,y) in the plane is \sqrt{x^2+y^2}, but we know that \sqrt{f(x,y)} and f(x,y) share the same critical points, so we need only worry about minimizing x^2+y^2. The Lagrangian for this problem is then

L(x,y,\lambda)=x^2+y^2+\lambda(x+7y-10)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0

L_y=2y+7\lambda=0

L_\lambda=x+7y-10=0

We have

L_y-7L_x=2y-14x=0\implies y=7x

which tells us that

x+7y-10=0\iff x+49x=10\implies x=\dfrac15\implies y=\dfrac75

so that \left(\dfrac15,\dfrac75\right) is a critical point. The Hessian for the target function x^2+y^2 is

H(x,y)=\begin{bmatrix}2&0\\0&2\end{bmatrix}

which is positive definite for all x,y, so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is \sqrt{\left(\dfrac15\right)^2+\left(\dfrac75\right)^2}=2.

3 0
2 years ago
A test is conducted to compare the tread wear of certain type of tires on highways paved with asphalt and highways paved with co
zimovet [89]

Answer:

Yes it does

Step-by-step explanation:

We can use two sample t-test to draw the conclusuion. However, by looking at the information of mileage of tyres on asphalt and concrete-paved highways, we can say that since mean milege of tyres on concrete is lesser, tyres wear faster on concrete-paved highways.

4 0
1 year ago
The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =
madreJ [45]
So we are given a system:
3x-2y+3z=0\\
-3x - 5y - 5z= -21
Substitute x = 2 we get the system:
-2y+3z=-6\\
- 5y - 5z= -15
Multiply the first equation by -5 and the second by 2 we get the system:
10y-15z=30\\
- 10y - 10z= -30
Adding the two equations we get :
-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
-2y=-6\\y=3.
Final solution:
z=0,y=3
8 0
1 year ago
Read 2 more answers
Write the fraction in ascending order.​
sveta [45]

from most to least:

i: 1/2, 1/3, 1/7, 1/10

ii: 2/3, 2/5, 2/9, 2/11

iii: 5/6, 3/4, 2/3, 1/2

iv: 4/5, 3/4, 5/8, 1/2

7 0
1 year ago
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