Answer: <em> 
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Step-by-step explanation:
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The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />
The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.
You can follow these steps in order to find the GCF:
1. You must decompose 27, 45, 108 and 126into their prime factors:
2. You must multiply the commons with the lowest exponents. Then:
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Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:
178.50 = 11.90y + 10.50x ⇒ equation in standard form.
Answer:
5901
Step-by-step explanation:
The margin of error is the critical value times the standard error.
ME = CV × SE
For α = 0.05, the critical value is z = 1.96.
The standard error of a proportion is √(pq/n). Given p = 0.04, then q = 1−p = 0.96.
The margin of error is 0.5% or 0.005.
Plugging in:
0.005 = 1.96 √(0.04 × 0.96 / n)
n ≈ 5901
Answer:
x = 5, x = 15; The zeros represent the number of photos printed to produce a maximum profit.
Step-by-step explanation:
F(x) = −x²+ 20x − 75
Let's f(x)= 0
0= -x²+20x-75
0= x²-20x+75
0=x²-5x-15x+75
0= x(x-5)-15(x-5)
0= (x-5)(x-15)
The zeros are
X= 5 or x = 15
And the xeros represent a number of photos printed to produce maximum profit
We have the following equation:
If we graph this equation we realize that in fact this is an ellipse with
major axis matching the y-axis. So we can recognize these characteristics:
1. Center of the ellipse: The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
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2. Length of major axis:
The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>
3. Length of minor axis:
The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:
4. Foci:Let's find c as follows:
Then the foci are:
