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VARVARA [1.3K]
1 year ago
15

A new technology for the production of integrated circuits is being mastered. The technology will be rejected if the percentage

of the defective integrated circuits exceeds 2%. How many integrated circuits have to be checked to make sure that the technology gives a sufficiently small amount of defects with a probability of 0.5% if the actual probability is p = 0.04? Use a = 0.05. Use the z-values rounded to two decimal places to obtain the answer. n = the absolute tolerance is +/-1
Mathematics
1 answer:
max2010maxim [7]1 year ago
8 0

Answer:

5901

Step-by-step explanation:

The margin of error is the critical value times the standard error.

ME = CV × SE

For α = 0.05, the critical value is z = 1.96.

The standard error of a proportion is √(pq/n).  Given p = 0.04, then q = 1−p = 0.96.

The margin of error is 0.5% or 0.005.

Plugging in:

0.005 = 1.96 √(0.04 × 0.96 / n)

n ≈ 5901

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at an amusement park, Robin bought a t-shirt for $8 and 5 ticket for ride. she spent a total of $23. How much did each ticket co
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Each ticket cost $3

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Look at Andrea’s running journal.
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First align the decimal points and the numbers,  then add the extra 0's if needed. Lastly, add and the total answer is 14.225.

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You are traveling down a country road at a rate of 95 feet/sec when you see a large cow 300 feet in front of you and directly in
emmainna [20.7K]

Answer:

1) You can rely solely on your brakes because when doing so the car will just travel 250ft from the point you hit your brakes till the point the car stopped completely, leaving you 50ft away from the cow.

2) See attached picture.

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in ft/s^{2}

3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) j(t)=\left \{ {{95t-9t^{2}; 0\le t

j'(t)=\left \{ {{95-18t; 0\leq t

(see attached picture for graph)

Step-by-step explanation:

1) In this part of the problem we need to find the time when the speed of the car is 0. Gets to a complete stop. For this we will need to take the derivative of the position function so we get:

j(t)=95t-9t^2

j'(t)=95-18t

and we set the first derivative equal to zero so we get:

95-18t=0

and solve for t

-18t=-95

t=\frac{95}{18}

t=5.28s

so now we calculate the position of the car after 5.28 seconds, so we get:

j(5.28)=95(5.28)-9(5.28)^{2}

j(5.28)=250.69ft

so we have that the car will stop 250.69ft after he hit the brakes, so there will be about 50ft between the car and the cow when the car stops completely, so he can rely just on the breaks.

2) For answer 2 I take the second derivative of the function so I get:

j(t)=95t-9t^{2}

j'(t)=95-18t

j"(t)=-18

and then we graph them. (See attached picture)

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in ft/s^{2}

3)  yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) j(t)=\left \{ {{95t-9t^{2}; 0\le t

j'(t)=\left \{ {{95-18t; 0\leq t

(see attached picture for graph)

5 0
1 year ago
The time it takes a printer to print a job is an Exponential random variable with the expectation of 12 seconds. You send a job
Mnenie [13.5K]

Answer:

0.8753

Step-by-step explanation:

Calculate the probability that your job will be ready before 10.01 am

Here, the parameter of an Exponential is E(X)=12

Now, to calculate the third job probability, it follows Poisson Distribution with parameter 1/λ

Therefore, E(Y) =1/12

Here, The third job will be ready for 10:01 AM, then E(Y)=61/12

Therefore, the required probability is

P(X\geq 3)=1-P(X

=1- POISSON(3,5,true)

=1-0.1246

=0.8753

8 0
2 years ago
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