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2 years ago

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Clayton Road is 2.25 miles long. Wood Pike Road is 1.8 miles long. Kisha used a quick picture to find the combined length of Cla

yton Road and Wood Pike Road. Does Kisha's work make sense? Explain why or why not.

1 answer:

tatuchka [14]2 years ago

7 0

I may ask, where is Kisha’s work?

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Check all statements that are equivalent to If the sky is not clear, then you don't see the stars ? a. Clear sky is necessary an

IrinaVladis [17]

Answer: The answer is G

Step-by-step explanation:

If you don't see the stars, then the sky is not clear. This statement is equivalent to saying "If the sky is not clear, then you don't see the stars", because if you rearrange both statements you will find out that they are equivalent to each other.

Mark out all the words in each statement, you will discover that at the end you will have no word left on both side, its just as good as saying 1 - 1 = 0.

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2 years ago

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Find a right triangle that has legs with your irrational Lengths and a hypotenuse with a rational Length

cluponka [151]

gg easy

the legs of a triangle are related as $a^2+b^2=c^2$ wehre a, b, and c are the legs and the hypotonuse of a triangle respectively

let's find some stuff

one easy way is to find a rational value for c find values of a and b

lets pick c=5

$a^2+b^2=5^2$

$a^2+b^2=25$

now split up 25 into 2 things that don't have rational square roots

if we say $a^2=19$ and $b^2=6$ then we get

$a=\sqrt{19}$ and $b=\sqrt{6}$ (which are both irrational)

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1 year ago

Negative 120 divided by 15

madreJ [45]

-120 ÷ 15 = -8.

Hope this helps.

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1 year ago

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W = 3x + 7y solve for y

mario62 [17]

Answer:

The value of the equation $y=\frac{W-3x}{7}$ .

Step-by-step explanation:

Consider the provided equation.

$W = 3x + 7y$

We need to solve the provided equation for y.

Subtract 3x from both side.

$W-3x= 3x-3x+ 7y$

$W-3x=7y$

Divide both sides by 7.

$\frac{7y}{7}=\frac{W-3x}{7}$

$y=\frac{W-3x}{7}$

Hence, the value of the equation is $y=\frac{W-3x}{7}$ .

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2 years ago

According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1

JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means $p=0.10$ and $q=1-0.10=0.90$ .

If 1100 Americans are sampled, then the sample size is $n=1100$ .

The mean of the distribution is $\mu=np$ .

This means $\mu=1100\times 0.10=110$

The standard deviation is $\sigma=\sqrt{npq}$

We substitute the values to get:

$\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95$

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: $P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)$

We now convert to Z-scores to get:

$P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\$

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)$

We convert to z-scores:

$P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48$

From the normal distribution, P(z>164.5)=0

c) First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\le88)=P(X\:$

We convert to z-scores:

$P(X\:$

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

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2 years ago