Let x be a random variable representing the number of skateboards produced
a.) P(x ≤ 20,555) = P(z ≤ (20,555 - 20,500)/55) = P(z ≤ 1) = 0.84134 = 84.1%
b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%
c.) P(x ≤ 20,445) = P(z ≤ (20,445 - 20,500)/55) = P(z ≤ -1) = 1 - P(z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%
The total number of possible classifications for the students of this college is found by multiplying 4 (which is the classification for the year level:freshman, sophomore, juniou, senior) and 2 (which is the number of sexes: female and male). So 4 x 2 = 8. There are eight possible classifications, which are:
(Male, Freshman)
(Male, Sophomore)
(Male, Junior)
(Male, Senior)
(Female, Freshman)
(Female, Sophomore)
(Female, Junior)
(Female,Senior)
Answer:
Karson's average speed on his way home was 28 miles per hour.
Step-by-step explanation:
Since Karson drove from his house to work at an average speed of 35 miles per hour, and the drive took him 20 minutes, if the drive took him 25 minutes and he used the same route in reverse, to determine what was his average speed going home, the following calculation must be performed:
60 = 35
20 = X
20 x 35/60 = X
700/60 = X
11.666 = X
25 = 11,666
60 = X
60 x 11.666 / 25 = X
27.99 = X
Therefore, Karson's average speed on his way home was 28 miles per hour.
Answer:
The predicted number of wins for a team that has an attendance of 2,100 is 25.49.
Step-by-step explanation:
The regression equation for the relationship between game attendance (in thousands) and the number of wins for baseball teams is as follows:
Here,
<em>y</em> = number of wins
<em>x</em> = attendance (in thousands)
Compute the number of wins for a team that has an attendance of 2,100 as follows:
Thus, the predicted number of wins for a team that has an attendance of 2,100 is 25.49.
