The function f(x) = xπ−−√ gives the diameter, in inches, of a proposed spherical sculpture with a surface area of x square inche
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Answer:
Option B. 1990 - 1992
Step-by-step explanation:
If we have to calculate inflation rate in year 2000 from 1990, we use the formula
which means if consumer price index is increasing year by year the inflation rate will increase.
Now we analyse our options given with the help of graph given.
A. from 1994 - 2000
Consumer price index increased from year 1994 to 1998 but decreased between 1998 to 2000.
So this option doesn't show the continuous inflation.
B. Year 1990 - 1992
We find a continuous increase in C.P.I. therefore there will be a continuous increase in inflation.
So this option is correct.
C. Year 1992 - 1996
In this gap we see deflation from year 1992 to 1994 then inflation between 1994 - 1996.
So there is ups and downs in this period showing discontinuity in inflation.
D. 1992 - 1994
There is continuous decrease in C.P.I. so continuous deflation is reported between this period.
It's not the correct option.
Answer is Option B.
Option C: –10, –7.5, –5, –2.5, … is the sequence that could be partially defined by the recursive formula
Explanation:
The given recursive formula is for
and
We need to determine the sequence.
The sequence can be determined by substituting n = 1, 2, 3, 4,....
<u>2nd term of the sequence:</u>
Substituting n = 1 in the formula , we get,
Simplifying, we have,
Thus, the 2nd term of the sequence is -7.5
<u>3rd term of the sequence:</u>
Substituting n = 2 in the formula , we get,
Simplifying, we have,
Thus, the 3rd term of the sequence is -5
<u>4th term of the sequence:</u>
Substituting n = 3 in the formula , we get,
Simplifying, we have,
Thus, the 4th term of the sequence is -2.5
Therefore, the sequence is –10, –7.5, –5, –2.5, …
Hence, Option C is the correct answer.
Answer:
The standard deviation of the number of rushing yards for the running backs that season is 350.
Step-by-step explanation:
Consider the provided information.
The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.
Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.
Use the formula:
Here z is 2.42 and μ is 790, substitute the respective values as shown.
Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.