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natita [175]
1 year ago
9

How many natural numbers lie between 75² and 76²​

Mathematics
1 answer:
vodomira [7]1 year ago
5 0

Answer:

Natural numbers between 75^{2} and 76^{2} is

(76 * 76) - (75 * 75)

=> 5776 - 5625

=> 151

Therefore, there are 151 natural numbers between 75^{2} and 76^{2}

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

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Ebola has an Ro of 2. How<br> many third-wave cases can<br> doctors expect?
stellarik [79]

Answer:

4 I guess

Step-by-step explanation:

Because

3-1=2

2^2=2*2=4

4 0
2 years ago
Jeremy is making a trail mix containing raisins and peanuts. Raisins cost $1.50 per pound. Peanuts cost $2.50 per pound. Jeremy
Kobotan [32]
<span>The answer is c. 1.5r + 2.5(5 – r) = 10.50. Let r be the number of raisins and p be the number of peanuts. Raisins cost $1.50 per pound: 1.5r. Peanuts cost $2.50 per pound: 2.5p. Jeremy spends $10.50: 1.50r + 2.50p = 10.50. Jeremy makes 5 pounds of trail mix: r + p = 5. So, we have the system of two equations: 1.5r + 2.5p = 10.50 and r + p = 5. Use the second equation to express p: p = 5 - r. Now, substitute p in the first equation: 1.5r + 2.5(5 - r) = 10.50. Therefore, the correct choice is c. 1.5r + 2.5(5 – r) = 10.50.</span>
4 0
1 year ago
Read 2 more answers
120÷(18-(20-3(9-5)simplify​
Ilya [14]

Answer:

20÷[18-{20-3(4)}]

120÷[18-[20-12]]

120÷[18-8]]

120÷10

12

Step-by-step explanation:

6 0
2 years ago
A hospital cafeteria has 20 20 tables. 65% 65 % of the tables have 6 6 chairs at each table. The remaining 35% 35 % of the table
miss Akunina [59]

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{65\% of 20}}{\left( \cfrac{65}{100}\right)20}\implies 13


so, 13 of the 20 tables have 6 chairs each.

that means, the remaining 7 tables, have 4 chairs each.

13 * 6 = 78 chairs total for those 13 tables.

7 * 4 = 28 chairs total for the remaining 7 tables.

78 + 28, that's how many.

4 0
2 years ago
Read 2 more answers
Tickets to a musical cost $30 for adults and $12 for children. At one particular performance 960 people attended and $19 080 was
postnew [5]
In order to solve this, you have to set up a systems of linear equations.

Let's say that children = c and adults = a

30a + 12c = 19,080
a + c = 960

I'm going to show you how to solve this system of linear equations by substitution, the easiest way to solve in my opinion.

   a + c = 960 
       - c    -    c
 ---------------------- ⇒ Step 1: Solve for either a or c in either equation.
   a = 960 - c 



20(960 - c)+ 12c = 19,080
19,200 - 20c + 12c = 19,080
   19,200 - 8c = 19,080
 - 19,200         - 19,200
---------------------------------- ⇒ Step 2: Substitute in the value you got for a or c
         8c = -120                    into the opposite equation.                                                
       ------  ---------
          8         8
 
         c = -15



30a + 12(-15) = 19,080
   30a - 180 = 19,080
          + 180  +     180
 -------------------------------
   30a = 19,260
  -------   -----------
    30          30
     
       a = 642
__________________________________________________________

I just realized that there can't be a negative amount of children, so I'm sorry if these results are all wrong. 


7 0
2 years ago
Read 2 more answers
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