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AysviL [449]
2 years ago
15

−15x+4≤109 OR −6x+70>−2

Mathematics
2 answers:
Xelga [282]2 years ago
3 0

-15x+4\leq109\qquad\text{subtract 4 from both sides}\\\\-15x\leq105\qquad\text{change the signs}\\\\15x\geq-105\qquad\text{divide both sides by 15}\\\\\boxed{x\geq-7}\\or\\-6x+70>-2\qquad\text{subtract 70 from both sides}\\\\-6x>-72\qquad\text{change the signs}\\\\6x

wlad13 [49]2 years ago
3 0

Answer:

all values of x are solutions

Step-by-step explanation:

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How to decompose a rectangle into two or three smaller rectangles to demonstrate the distributive property?
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Answer:

See explanation

Step-by-step explanation:

The distibutive property states that for all real numbers a, b and c

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Divide this rectangle into two rectangles: first rectangle with the length of a units and the width of c units and the second rectangle with the length of b units and the width of c units. The area of these rectangles are

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2 years ago
A rectangular room has a width of 5 yards and length of 6 yards. How many square-feet carpet will be required for carpeting the
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Answer:

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Step-by-step explanation:

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Tickets to a movie cost $5 for adults and $3 for students. A group of friends purchased 18 tickets for $82.00. How many adults t
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Data from 14 cities were combined for a​ 20-year period, and the total 280 ​city-years included a total of 107 homicides. After
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Answer:

P(0) =  0.6825

P(1) = 0.2607

Step-by-step explanation:

From the given information, the number of homicide is 107 and the total number of homicides per city –year is 280.

Let us denote the number of homicides per city-year as X.

The mean value, X is calculated as:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}  

Mean=   107/280 = 0.382  

The mean number of homicides per city- year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. The probability that zero homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=0) =  e  −0.382  (0.382)⁰​/1  

= (0.6825)(1) /1  

P(X=0) = 0.6825

Thus, the probability that zero homicides P(0) is 0.6825.

b. The probability that one homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=1) =  e  −0.382  (0.382)¹​/1  

= (0.6825)(0.382)/1  

P(X=1) = 0.2607

Thus, the probability that zero homicides P(0) is 0.2607.

​

5 0
2 years ago
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