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Tpy6a [65]
1 year ago
10

each transformation is performed on the line with the equation y=2x-1. write the equation of the new line. vertical translation

down 3 units, slope increased by 4, slope divided in half, and shifted up 1 unit.
Mathematics
1 answer:
Phoenix [80]1 year ago
6 0

Answer:

y2= 2x-4

y3=6x-1

y4= x-1

y5=2x

Step-by-step explanation:

for y=2x-1

1) for a vertical translation down of 3 units

y2= y-3 =(2x-1)-3= 2x-4

y2= 2x-4

2) for a slope increased by 4

y3= y+ 4x = 2x-1 +4x = 6x-1

y3=6x-1

3) for sloped divided in half. slope of y : m=2 → slope of y4=2/2 =1

y4= x-1

4) shifted up (vertical translation) of  1 unit

y5= y+1 = 2x-1+1=2x

y5=2x

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marishachu [46]

Answer:

2.2 minutes

Step-by-step explanation:

38.5 ÷ 17.5 = 2.2

4 0
2 years ago
PLEASE HELP ASAP: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of z
dimaraw [331]
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4) When 0\ \textless \ t\ \textless \ \frac{9}{2} the particle is slowing down because the acceleration is close to zero \Rightarrow the particle is speeding up when acceleration is increasing away from zero: \frac{9}{2}\ \textless \ t\ \textless \ 8.
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3 0
2 years ago
2 inches 3 inches Pivot. If 60 lbs. of force must be applied to the valve for it to open, how much upward force must push rod X
tresset_1 [31]

We can solve this problem by stating that the summation of momentums must be zero. That is, the momentum at one end of the pivot must be equal to the momentum at the other end.

Momentum 1 = Momentum 2

Since Momentum is the product of Force and Distance, and with this rule created, we can say that:

F1 * d1 = F2 * d2

Where,

F1 = 60 lbs

d1 = 2 inches from the pivot

F2 = unknown X

d2 = 3 inches from the pivot

Substituting to the equation to find for F2:

60 lbs * 2 inches = F2 * 3 inches

F2 = 40 lbs

 

<span>Therefore 40 lbs of upward force must be pushed to open the valve.</span>

<span>Answer: B</span>

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vagabundo [1.1K]

Answer:

the ablity to choose one is the right now

Step-by-step explanation:

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1 year ago
(b) we often read that iq scores for large populations are centered at 100. what percent of these 78 students have scores above
zheka24 [161]
Given that the<span> iq scores for large populations are centered at 100.

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P(x > 100) = P(z > (100 - 100)/sd) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 0.5 = 50%
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