Answer:
the probability that randomly selected applicants over 10 years of experience is 0.6791
Step-by-step explanation:
The computation of the probability that randomly selected applicants over 10 years of experience is as follows:
Total would be
= 187 have 10 + years experience
Now
P(graduate | 10+) = (graduate and 10+ years experience) ÷ (10 + years of experience)
= 127 ÷ 187
= 0.6791
Hence, the probability that randomly selected applicants over 10 years of experience is 0.6791
Hope this is what you need
Answer:
A + B + C = π ...... (1)
...........................................................................................................
L.H.S.
= ( cos A + cos B ) + cos C
= { 2 · cos[ ( A+B) / 2 ] · cos [ ( A-B) / 2 ] } + cos C
= { 2 · cos [ (π/2) - (C/2) ] · cos [ (A-B) / 2 ] } + cos C
= { 2 · sin( C/2 ) · cos [ (A-B) / 2 ] } + { 1 - 2 · sin² ( C/2 ) }
= 1 + 2 sin ( C/2 )· { cos [ (A -B) / 2 ] - sin ( C/2 ) }
= 1 + 2 sin ( C/2 )· { cos [ (A-B) / 2 ] - sin [ (π/2) - ( (A+B)/2 ) ] }
= 1 + 2 sin ( C/2 )· { cos [ (A-B) / 2 ] - cos [ (A+B)/ 2 ] }
= 1 + 2 sin ( C/2 )· 2 sin ( A/2 )· sin( B/2 ) ... ... ... (2)
= 1 + 4 sin(A/2) sin(B/2) sin(C/2)
= R.H.S. ............................. Q.E.D.
...........................................................................................................
In step (2), we used the Factorization formula
cos x - cos y = 2 sin [ (x+y)/2 ] · sin [ (y-x)/2 ]
Step-by-step explanation:
Hi Kay, the point-slope form of a line is given by: y - y1 = m(x - x1). Substituting the given point, (6, -8), and the slope, -2, gives: y - (-8) = -2 * (x - 6) This becomes: y + 8 = -2x + 12
Answer:
A. $301
B. $721
Step-by-step explanation:
Let $x be the amount of money they raised.
Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then
Polly tried to put the $1 bills into three equal piles and found one left over at the end, then
Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then
Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then
This means 
is divisible by 2, 3, 4, 5 and 6 without remainder, so
Hence,
The smallest amount of money they could have raised is $301, because
is divisible by 7.
Now, the number 
should be divisible by 7 and must be greater than 500.
So,
When n = 9,
is not divisible by 7.
When n = 10,
is not divisible by 7.
When n = 11,
is not divisible by 7.
When n = 12,
is divisible by 7.
B. The least amount of money they could have raised is $721
