Answer:
4. A) 
3. A) 
2. D) 
1. C) 
Step-by-step explanation:
4. Two families combined have <em>at</em><em> </em><em>least</em><em> </em>3 pets.
3. $1500 is your result, so everything else is straightforward simple, knowing that the keywords <em>at</em><em> </em><em>least</em><em> </em>$1500<em> </em>mean <em>greater</em><em> </em><em>than</em><em> </em><em>or</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em>$1500.
2. Find the correspondents, then determine what inequality to use. In this case, you will use <em>less than</em><em> </em><em>or equal</em><em> </em><em>to</em><em> </em>because overpaying is UNNECESSARY.
1. <em>Eight</em><em> </em><em>dollars</em><em> </em><em>each</em><em> </em><em>pizza</em><em> </em>and <em>twelve</em><em> </em><em>dollars</em><em> </em><em>each</em><em> </em><em>pizza</em><em> </em>is <em>12x</em><em> </em>and <em>8x</em>.<em> </em>The rest is straightforward simple because you now have your <em>initial</em><em> </em><em>costs</em><em> </em>of <em>$</em><em>45</em><em> </em>and <em>$</em><em>5</em>,<em> </em>and the exercise tells you that the total charge for Company A is <em>less than</em> the total charge for Company B, therefore you have your answer.
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Answer:
There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>
Step-by-step explanation:
Let p1 be the proportion of West University students who involved in a car accident within the past year
Let p2 be the proportion of East University students who involved in a car accident within the past year
Then
p1=p2
p1≠p2
The formula for the test statistic is given as:
z=
where
- p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
- p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
- p is the pool proportion of p1 and p2 (
) - n1 is the sample size of the students from West University (100)
- n2 is the sample size ofthe students from East University (100)
Then we have z=
≈ 0.6208
Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.
<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance
we know that
Each meter of ribbon cost 
so
by proportion
Find the cost of 
meters of ribbon
therefore
<u>the answer is</u>
The ribbon cost 
What is the question u are asking?
Answer:
the modem is $8 per month
Step-by-step explanation:
