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jekas [21]
2 years ago
14

HELP

Mathematics
2 answers:
Darina [25.2K]2 years ago
5 0
B is the answer I think
mr Goodwill [35]2 years ago
3 0

Answer:

b should be the answer i think

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The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic
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The rest of the queastion is :
<span> A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================
</span>

<span>The distance between two points (x₁,y₁),(x₂,y₂) = d
d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }</span>


we have <span>K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = </span><span>d = \sqrt{ (5-1)^{2} + (4-1)^{2} } = 5
</span>LM = <span>d = \sqrt{ (5-5)^{2} + (1-4)^{2} } = 3
KM = </span><span>d = \sqrt{ (5-1)^{2} + (1-1)^{2} } = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
</span>The correct choice is C
<span>C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
</span><span>K'(-1, 1), L'(-4, 5), M'(-1, 5)
</span>
<span>K'L' = <span>d = \sqrt{ (-4+1)^{2} + (5-1)^{2} } = 5
</span>L'M' = <span>d = \sqrt{ (-1+4)^{2} + (5-5)^{2} } = 3
K'M' = </span><span>d = \sqrt{ (-1+1)^{2} + (5-1)^{2} } = 4</span></span>
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Past studies indicate that about 60 percent of the trees in a forested region are classified as softwood. A botanist studying th
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Answer:

1. If it is true that 60 percent of the trees in a forested region are classified as softwood, 0.015 is the probability of obtaining a population proportion greater than 0.6.

Step-by-step explanation:

Hello!

The historical information indicates that 60% of the forest trees are classified as softwood.

A botanist thinks that the proportion might be greater than 60%, so he tested his belief obtaining:

H₀: p = 0.60

H₁: p > 0.60

p-value: 0.015

You need to interpret this p-value. Little reminder:

The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis. It represents the % of size n samples from a population with proportion p=p₀, which will produce a measure that provides evidence as (or stronger) than the current sample that p is not equal to p₀.

The correct answer is:

1. If it is true that 60 percent of the trees in a forested region are classified as softwood, 0.015 is the probability of obtaining a population proportion greater than 0.6.

I hope this helps!

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Answer:

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Step-by-step explanation:

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