Drew burned 1,800 calories Friday playing 1 hour of basketball and canoeing for 2 hours. On Saturday, he spent 2 hours playing b
asketball and 3 hours canoeing and burned 3,200 calories. How many calories did he burn per hour when playing basketball?
2 answers:
Answer:
He burn 1000 calories per hour when playing basketball
Step-by-step explanation:
Let x be the no. of calories burnt per hour while playing Basketball
Let y be the no. of calories burnt per hour while canoeing
We are given that Drew burned 1,800 calories Friday playing 1 hour of basketball and canoeing for 2 hours.
So, Equation becomes = --- A
On Saturday, he spent 2 hours playing basketball and 3 hours canoeing and burned 3,200 calories.
So, Equation becomes = --- B
Plot A and B
---- Black
--- Red
Refer the attached figure
Intersection point gives the solution
(x,y)=(1000,400)
So, he burn 1000 calories per hour when playing basketball
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That height is 3.975 meters.
_____
f(x) = g(x)
-4.9x^2 +15 = -4.9x^2 +10x
15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
1.5 = x . . . . . . . . . . . . . . . . . . . divide by 10
f(1.5) = -4.9*2.25 +15 = 3.975
That height is 3.975 meters.
_____
f(x) = g(x)
-4.9x^2 +15 = -4.9x^2 +10x
15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
1.5 = x . . . . . . . . . . . . . . . . . . . divide by 10
f(1.5) = -4.9*2.25 +15 = 3.975
Answer:
The correct option is: If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained
Step-by-step explanation:
Consider the provided information.
The Null hypotheses is 57%,
P-value is given as 0.026
Here P value represents the probability.
0.026 can be written as: 2.6%
Thus the conclusion is:
If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained.
Hence, the correct option is: If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained
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