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IrinaK [193]
2 years ago
13

A penny collection contains twelve 1967 pennies, seven 1968 pennies, and eleven 1971 pennies. If you are to pick some pennies wi

thout looking at the dates, how many must you pick to be sure of getting at least six pennies from the same year
Mathematics
1 answer:
IgorC [24]2 years ago
5 0

Answer:

12 because of a 40 percent of 20 as 12 we know that there is a possiblity of almost all of the 12 to be 1967.

Step-by-step explanation:

You might be interested in
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
2 years ago
Read 2 more answers
Need help asap. Consider the diagram.
fgiga [73]

ANSWER

<em>alternate interior angles theorem</em>

EXPLANATION

According to the alternate interior angles theorem, when two parallel lines are are intercepted by a straight line (transversal) the angles in the interior corners of a Z-shape pattern are congruent.

From the above diagram line r is parallel to line s, therefore

\angle \: 3 \cong \angle6

and

\angle \: 4\cong \angle5

because they are alternate interior angles.

See attachment for how to spot alternate interior angles.

5 0
2 years ago
Read 2 more answers
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is
stealth61 [152]

Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
2 years ago
Jose and Maris work for different car dealerships. Jose earns a monthly salary of $3,500 plus a 6% commision on his sales, x. Ma
patriot [66]

Answer:

x>$25000

Step-by-step explanation:

4 0
2 years ago
Find the length of 2004-04-02-01-00_files/i0230000.jpg. Round the answer to the nearest hundredth.
notsponge [240]
The answer should be b
8 0
2 years ago
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